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poizon [28]
2 years ago
13

Grace is looking at a report of her monthly cell-phone usage for the last year to determine if she needs to upgrade her plan. Th

e list represents the approximate number of megabytes of data Grace used each month.700, 735, 680, 890, 755, 740, 670, 785, 805, 1050, 820, 750What is the standard deviation of the data? Round to the nearest whole number
Mathematics
2 answers:
Nina [5.8K]2 years ago
8 0

Answer:

100

Step-by-step explanation:

The list represents the approximate number of megabytes of data Grace used each month.700, 735, 680, 890, 755, 740, 670, 785, 805, 1050, 820, 750

Total number of observations = 12

Mean = \frac{\text{Sum of all observations}}{\text{Total no. of observations}}

Mean = \frac{700+735+680+890+755+740+ 670+785+805+ 1050+820+750}{12}

Mean = 781.666

So, \bar{x}=781.666

Standard deviation = \sigma = \sqrt{\frac{\sum(x_i-{x})^2}{n}}

So, \sigma = \sqrt{\frac{(700-781.666)^2+(735-781.666)^2+(680-781.666)^2+(890-781.666)^2+(755-781.666)^2+(740-781.666)^2+(670-781.666)^2+(785-781.666)^2+(805-781.666)^2+(1050-781.666)^2+(820-781.666)^2+(750-781.666)^2}{12}}

\sigma = 100.36

So,  the standard deviation of the data round to the nearest whole number is 100

Mkey [24]2 years ago
4 0
The answer for this one is 100
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Answer:

$163.54

Step-by-step explanation:

Volume of rectangular container = 10m^3

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Step-by-step explanation:

We are given that a 20 kg cylindrical  mass is dropped onto the mat from a height of 1 m above the mat. During the impact,  the cylinder’s vertical velocity reaches zero at the instant the mat has compressed to  only 4 cm thick.

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