Write an integer whose absolute value is greater than itself.

1 answer:

3 0

The integer -1 has an absolute value of 1, which is greater than itself. Since all negative integers are by definition integers, their respective absolute values will be greater than themselves.

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Express 75 kobo as a decimal of 1 naira 50 kobo

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0.005

Step-by-step explanation:

75/50 = 1.5

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A researcher took a random sample of 100 students from a large university. She computed a 95% confidence interval to estimate th

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Answer:

Part (A): The correct option is true.

Part (B): The null and alternative hypothesis should be:

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Step-by-step explanation:

Consider the provided information.

Part (A)

A random sample of 100 students from a large university.

Increasing the sample size decreases the confidence intervals, as it increases the standard error.

If the researcher increase the sample size to 150 which is greater than 100 that will decrease the confidence intervals or the researcher could produce a narrower confidence interval.

Hence, the correct option is true.

Part (B)

The researcher wants to identify that whether there is any significant difference between the measurement of the blood pressure.

Therefore, the null and alternative hypothesis should be:

$H_o: \mu =0 ; H_a:\mu \neq0$

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For each pair of expressions below, without substituting in specific values, determine which of the expressions in the given pai

miv72 [106K]

Answer:

5+t²
15/x²
it depends (see below)
it depends (see below)

Step-by-step explanation:

1. t² is a positive number. Adding a positive number to 5 will always produce a larger result than subtracting the same positive number from 3. The larger expression is 5+t².

2. The expressions are only defined for x ≠ 0, so for x² a positive number. For any x, the expressions are both positive. 15/(7x²) is 1/7 of 15/x², so will always be smaller. The larger expression is 15/x².

3. As in 2, these expressions are only defined for x ≠ 0. One expression is the opposite of the other. A number is greater than its opposite when it is positive, so 1/x > 1/-x for x > 0; and 1/-x > 1/x for x < 0.

4. The expression (k -6)² has the same range of values as k², but its graph is shifted 6 units to the right. The left branch of (k -6)² will be greater than k² for any k < 3. Similarly, the right branch of k² will be greater than (k -6)² for any k > 3.