Answers:
A) △ACF ≅ △AEB because of ASA.
D) ∠CFA ≅ ∠EBA
E) FC ≅ BE
Solution:
AC ≅ AE; ∠ACD ≅ ∠AED Given
The angle ∠CAF ≅ ∠EAB, because is the same angle in Vertex A
Then △ACF ≅ △AEB because of ASA (Angle Side Angle): They have a congruent side (AC ≅ AE) and the two adjacent angles to this side are congruent too (∠ACD ≅ ∠AED and ∠CAF ≅ ∠EAB), then option A) is true: △ACF ≅ △AEB because of ASA.
If the two triangles are congruent, the ∠CFA ≅ ∠EBA; and FC ≅ BE, by CPCTC (Corresponding Parts of Congruent Triangles are Congruent), then Options D) ∠CFA ≅ ∠EBA and E) FC ≅ BE are true
Answer:
0.67
Step-by-step explanation:
<u>Solution 1</u>
We can work out the initial number by going backwards from the end:
67/1000= 0.067
0.067*100= 6.7
6.7/10= 0.67
<u>Solution 2</u>
(x*10/100)*1000= 67
x/10*1000= 67
100x= 67
x=67/100
x=0.67
Answer:
0.4745 is the probability that fewer than 8 of the selected adults wear glasses or contact lenses.
Step-by-step explanation:
We are given the following information:
We treat adult adults wear glasses or contact lenses as a success.
P(Adults wear glasses or contact lenses) = 75% = 0.75
Then the number of adults follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 10
We have to evaluate:
P(fewer than 8 of the selected adults wear glasses or contact lenses)
0.4745 is the probability that fewer than 8 of the selected adults wear glasses or contact lenses.
The difference between the 2 times would be .055 seconds...
Answer:
mArc A B = 120° (C)
Step-by-step explanation:
Question:
In circle O, AC and BD are diameters.
Circle O is shown. Line segments B D and A C are diameters. A radius is drawn to cut angle D O C into 2 equal angle measures of x. Angles A O D and B O C also have angle measure x.
What is mArc A B?
a)72°
b) 108°
c) 120°
d) 144°
Solution:
Find attached the diagram of the question.
Let P be the radius drawn to cut angle D O C into 2 equal angle measures of x
From the diagram,
m Arc AOC = 180° (sum of angle in a semicircle)
∠AOD + ∠DOP + ∠COP = 180° (sum of angles on a straight line)
x° +x° + x° =180°
3x = 180
x = 180/3
x = 60°
m Arc DOB = 180° (sum of angle in a semicircle)
∠AOB + ∠AOD = 180° (sum of angles on a straight line)
∠AOB + x° = 180
∠AOB + 60° = 180°
∠AOB = 180°-60°
∠AOB = 120°
mArc A B = 120°