How to unscramble pirgenaet

The foodservice department has been asked to prepare a special luncheon for the grandway hospital board of directors on tuesday.

AURORKA [14]

125/21 = 150/x
cross multiply
125x = 3150
x = 3150/125
x = 25.2 lbs....rounded up = 26 lbs <==

5 0

2 years ago

The length of a rectangular rug is 4 feet less than twice its width. The perimeter of the rug is 40 feet. Write a system of equa

Brrunno [24]

Answer:

Step-by-step explanation:

L=2W-4

40=2L+2W

The first equation uses the information that the length of a rectangular rug is 4 feet less than twice its width.

The second equation is using your standard perimeter equation of 2L+2W=perimeter of a rectangle.

Hope this is helpful :)

6 0

2 years ago

Hey ^-^ can someone please help me with this problem:

soldi70 [24.7K]

Answer: 8 (Pi - sqrt(3))

Discussion:

The area of the shaded region is that of the semicircle minus the area of the triangle..

Area of semicircle = 1/2 * Pi * R^2

Where R^2 is the square of the radius of the circle. In our case, R ( = OC)

= 4 so the semicircle area is

(1/2) * Pi * (4^2) = (1/2) * Pi * 16 = 8 Pi

Area of triangle.

First of all, angle ACB is a right angle ( i.e. 90 degrees).

* This is the Theorem of Thales from elementary Plane Geometry. *

so by Pythagoras

AC^2 + BC^2 = AB^2

But CB = 4 (given) and AB = 4*2 = 8 ( the diameter is twice the radius).

Substituting these in Pythagoras gives

AC^2 + 4^2 = 8^2 or

AC^2 = 8^2 - 4^2- = 64 - 16 = 48

Hence AC = sqrt(48) = sqrt (16*3) = 4 * sqrt(3)

We are almost done! The area of the triangle is given by

(1/2) b * h = (1/2) BC * AC = (1/2) 4 * (4 * sqrt(3)) = 8 sqrt(3)

We conclude the area area of the shaded part is

8 PI - 8 sqrt(3) = 8 (Pi - sqrt(3))

Note that sqrt(3) is approx 1.7 so (PI - sqrt(3)) is a positive number, as it better well be!

6 0

2 years ago

In an experiment, some diseased mice were randomly divided into two groups. One group was given an experimental drug, and one wa

damaskus [11]

Answer:

D)Yes, because the difference in the means in the actual experiment was more than two standard deviations from 0.

Step-by-step explanation:

We will test the hypothesis on the difference between means.

We have a sample 1 with mean M1=18.2 (drug group) and a sample 2 with mean M2=15.9 (no-drug group).

Then, the difference between means is:

$M_d=M_1-M_2=18.2-15.9=2.3$

If the standard deviation of the differences of the sample means of the two groups was 1.1 days, the t-statistic can be calculated as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{2.3-(0)}{1.1}=2.09$

The critical value for a two tailed test with confidence of 95% (level of significance of 0.05) is t=z=1.96, assuming a large sample.

This is approximately 2 standards deviation (z=2).

The test statistict=2.09 is bigger than the critical value and lies in the rejection region, so the effect is significant. The null hypothesis would be rejected: the difference between means is significant.

4 0

2 years ago

The length of a rectangle is 9.7 cm more than 4 times the width. If the perimeter of the rectangle is 91.4 cm what are its dimen

goldfiish [28.3K]

I hope this helps you

8 0

2 years ago

Read 2 more answers