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Elina [12.6K]
2 years ago
3

You conduct a random survey of your small town about having a town wide garage sale. of those surveyed, 56% are in favor and 44%

are opposed. the actual percent could be 5% more or 5% less than the acquired results.
a. write and solve an absolute value equation to find the least and greatest percentage of your town population that could be opposed to a town wide garage sale.
Mathematics
1 answer:
Step2247 [10]2 years ago
8 0

We are given that the percentage who are opposed to the wide garage sale is 44%.

The range of deviation is 5% more or 5% less.

Therefore if we say that x is the percentage of the people who are opposed, then:

<span>|x – 44| = 5</span>

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Answer Please???? Finn is baking cakes for a party. The number of cups of sugar Finn needs is proportional to the number of cake
Natali [406]

Answer:

Hello there!

The answer to your question is :

<em>C: Finn needs 6 cups of sugar for 4 cakes.</em>

<em>D: Finn needs 1 1/2 cups of sugar for 1 cak</em>e.

Step-by-step explanation:

The graph clearly shows ( sides cups of sugar) (bottom number of cakes)

For sugar you need 6 cups to make 4 cakes

For sugar on the second question you need 1 1/2 cups of sugar to make 1 cake

Multiply 1 1/2 times 6 then divide and your answer is 4. That's 4 cakes out of 6 cups of sugar out of the original cups of sugar ( 1 1/2)


This is the confirmed answer I took the quiz and got 100%

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5 0
2 years ago
A store sells a 33-pound bag of oranges for \$ 3.60$3.60 and a 55-pound bag of oranges for \$ 5.25$5.25. What is the difference
katrin [286]

Answer:

0.01364

Step-by-step explanation:

It is given that,

A store sells a 33-pound bag of oranges for $3.60 and a 55-pound bag of oranges for $5.25.

Price per pound of 33 pound bag is 3.60/33 = 0.10909 price per pound

Price per pound of 55 pound bag of oranges is 5.25/55 = 0.09545 price per pound

Difference between price per pound for the 33-pound bag of oranges and the price per pound for the 55-pound bag of oranges is :

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I think it b on edg.

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Answer:

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Step-by-step explanation:

The method of reduction of order is applicable for second-order differential equations.

For a known solution y1 of a 2nd order differential equation, this method assumes a second solution in the form Uy1 which satisfies the said differential equation. It then assumes a reduced order for U'' (w' = U'').

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