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1 year ago

(5y + 2) + 14x = 5y + (2 + 14x)

2 answers:

5 0

6. (5y+2)+14x=5y+(2+14x) (1point) A.associative property of addition B.associative property of multiplication C.commutative property of addition D.commutative property of multiplication 7. (m*n)*p=m*(n*p) (1 point) A. commutative property of addition B.commutative property of multiplication C.associative property of addition D. associative property of multiplication

Lorico [155]1 year ago

3 0

Simplify brackets

5y+2+14x=5y+2+14x5y+2+14x=5y+2+14x
Since both sides equal, there are infinitely many solutions
Infinitely Many Solutions

SO BASICALLY THAT MEANS IT EQUALS TO 0.

Simplifying (5y + 2) + 14x = 5y + (2 + 14x) Reorder the terms: (2 + 5y) + 14x = 5y + (2 + 14x) Remove parenthesis around (2 + 5y) 2 + 5y + 14x = 5y + (2 + 14x) Reorder the terms: 2 + 14x + 5y = 5y + (2 + 14x) Remove parenthesis around (2 + 14x) 2 + 14x + 5y = 5y + 2 + 14x Reorder the terms: 2 + 14x + 5y = 2 + 14x + 5y Add '-2' to each side of the equation. 2 + 14x + -2 + 5y = 2 + 14x + -2 + 5y Reorder the terms: 2 + -2 + 14x + 5y = 2 + 14x + -2 + 5y Combine like terms: 2 + -2 = 0 0 + 14x + 5y = 2 + 14x + -2 + 5y 14x + 5y = 2 + 14x + -2 + 5y Reorder the terms: 14x + 5y = 2 + -2 + 14x + 5y Combine like terms: 2 + -2 = 0 14x + 5y = 0 + 14x + 5y 14x + 5y = 14x + 5y Add '-14x' to each side of the equation. 14x + -14x + 5y = 14x + -14x + 5y Combine like terms: 14x + -14x = 0 0 + 5y = 14x + -14x + 5y 5y = 14x + -14x + 5y Combine like terms: 14x + -14x = 0 5y = 0 + 5y 5y = 5y Add '-5y' to each side of the equation. 5y + -5y = 5y + -5y Combine like terms: 5y + -5y = 0 0 = 5y + -5y Combine like terms: 5y + -5y = 0 0 = 0 Solving 0 = 0 Couldn't find a variable to solve for.

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Visa Card USA studied how frequently young consumers, ages 18 to 24, use plastic (debit and credit) cards in making purchases (A

umka2103 [35]

Answer:

Given the consumer is 18 to 24 years old, there is 37% probability that he uses a plastic card.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem, we have:

What is the probability of the consumer using a plastic card, given that the consumer is 18 to 24 years old.

The problem states that the probability that a consumer uses a plastic card when making a purchase is .37, so $P(B) = 0.37$

P(A/B) is the probability that the consumer being 18 to 24 years old, given that he uses a plastic card. The problem states that this probability is .19. So $P(A/B) = 0.19$

P(A) is the probability that the consumer is 18 to 24 years old. There is a .81 probability that the consumer is more than 24 years old. So there is a .19 probability that he is 18 to 24 years old. So $P(A) = 0.19$

The probability is

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.37*0.19}{0.19} = 0.37$

Given the consumer is 18 to 24 years old, there is 37% probability that he uses a plastic card.

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2 years ago

State the complement of each of the following sets: (a) Engineers with less than 36 months of full-time employment. (b) Samples

iren2701 [21]

Answer:

(a) Engineers with greater than 36 months of full-time employment.

(b) Samples of cement blocks with compressive strength greater than 6000 kilograms per square centimeter

(d) Cholesterol levels that measure less than 180 and greater than 220.

Step-by-step explanation:

The complement of a set refers to elements that does not exist in that set. It means what does not exist in the set but exist in the universal set.

(a) Engineers with greater than 36 months of full-time employment.

In this case, the Universal set is a set of engineers in full-time employment. The given set is for engineers with less than 36 months of full-time employment. The complement is engineers with greater than 36 months of full-time employment.

(b) Samples of cement blocks with compressive strength greater than 6000 kilograms per square centimeter

In this case, the universal set is a set of samples of cement block having compressive strength. The given set is a set of cement block having compressive strength less than 6000 kilograms per square centimeter. The complement is samples of cement blocks with compressive strength greater than 6000 kilograms per square centimeter.

In this case, the universal set is a set of measurements of the diameter of forged pistons. The given set is a set of measurements of the diameter of forged pistons that do not conform to engineering specifications. The complement is a set of measurements of the diameter of forged pistons that conforms to engineering specification.

(d) Cholesterol levels that measure less than 180 and greater than 220.

In this case, the universal set is a set of Cholesterol levels. The given set is Cholesterol levels that measure greater than 180 and less than 220. The complement is Cholesterol levels that measure less than 180 and greater than 220.

5 0

1 year ago

Beau buys a skateboard with a price tag of $82.50. The tax rate is 8%. How much does he pay, including tax

madam [21]

8% of $82.50 is $6.60 so 82.50 + 6.60 would equal $89.10 as the total

7 0

1 year ago

Problem Lois and Clark own a company that sells wagons. The amount they pay each of their sales employees (in dollars) is given

Oxana [17]

12h + 30w.....where h = hrs worked and w = wagons sold

so if an employee works 6 hrs and sells 3 wagons....then h = 6 and w = 3

12h + 30w
12(6) + 30(3) =
72 + 90 = $ 162 <==

8 0

2 years ago

In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t

victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that he or she would choose the pair of socks in the center position is $p =\frac{1}{5}$

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5

The mean is $\mu = 20$

The standard deviation is $\sigma=4$

The probability, $P =0.0002$

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability $Pe = 0.0003$

The probabilities $P \approx Pe$

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

$p =\frac{1}{5}$

$=0.2$

The mean of this distribution is mathematical represented as

$\mu = np$

substituting the value

$\mu = 100 * 0.2$

$\mu = 20$

The standard deviation is mathematically represented as

$\sigma = \sqrt{np (1-p)}$

substituting the value

$= \sqrt{100 * 0,2 (1-0.2)}$

$\sigma=4$

Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

$P=P(X \ge 34 )$

By standardizing the normal approximation we have that

$P(X \ge 34) \approx P(Z \ge z)$

Now z is mathematically evaluated as

$z = \frac{x-\mu}{\sigma }$

Substituting values

$z = \frac{34-20}{4}$

$=3.5$

So using the z table the $P(Z \ge 3.5)$ is 0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

6 0

2 years ago