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fomenos
2 years ago
3

Write a program that lets a user enter n and that outputs n! (meaning n*(n-1)*(n-2)*...*2*1). hint: initialize a variable totalv

alue to n, and use a loop variable i that counts from n-1 down to 1.
Computers and Technology
1 answer:
uysha [10]2 years ago
3 0
//  This code snippet calculates n! and stores the answer in the variable p.
// Handle 0! = 1 separately.
if (n==0) {
   p = 1;
}
else {
// Initialize p = n
p = n;

// While loop
while (n>1) {
      p = p*(n-1);
      n = n-1;
     }
}

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solong [7]

Answer:

Explanation:

K- is the working procedure:

It takes n no. of predefined cluster as input and data points.

It also randomly initiate n centers of the clusters.

In this case the initial centers are given.

Steps you can follow

Step 1. Find distance of each data points from each centers.

Step 2. Assign each data point to the cluster with whose center is nearest to this data point.

Step 3. After assigning all data points calculate center of the cluster by taking mean of data points in cluster.

repeat above steps until the center in previous iteration and next iteration become same.

A1(4,8), A2(2, 4), A3(1, 7), B1(5, 4), B2(5,7), B3(6, 6), C1(3, 7), C2(7,8)

Centers are X1=A1, X2=B1, X3=C1

A1 will be assigned to cluster1, B1 will be assigned to cluster2 ,C1 will be assigned to cluster3.

Go through the attachment for the solution.

5 0
2 years ago
Annabeth has been using a public cloud to store and access her documents. Which drawback of a public cloud should she be aware o
Flura [38]

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5 0
2 years ago
we are given an array a consisting of n distinct integers. we would like to sort array A into ascending order using a simple alg
marta [7]

Answer:

Check the explanation

Explanation:

the js code is as follows

function count_max_group(ar) {

if (ar.length < 2) return ar.length; // if no of elements are 2 then max groups are 2

let st = [0]; // stack to store the groups

for (let i = 1; i < ar.length; i++) {

if (ar[i] >= ar[i - 1]) st.push(i); // pushing elements if if ar[i] is greater than the previous element

for (let j = i; j > 0 && ar[j] < ar[j - 1]; j--) { // finding the max number of grps

swap(ar, j, j - 1); // swapping

if (j <= st[st.length - 1]) st.pop();

}

}

return st.length;

}

function swap(a, i, j) { // function to swap two variables

let t = a[i];

a[i] = a[j];

a[j] = t;

}

//sample solutions

console.log("the sample solutions are\n");

console.log("[2,1,6,4,3,7]\n");

console.log(count_max_group([2,1,6,4,3,7]));

console.log("[4,3,2,6,1]\n") ;

console.log(count_max_group([4,3,2,6,1]));

console.log("[2,4,1,6,5,9,7]\n");

console.log(count_max_group([2,4,1,6,5,9,7]));

4 0
2 years ago
Write code which takes a user input of a String and an integer. The code should print each letter of the String the number of ti
il63 [147K]

import java.util.*;

public class myClass {

public static void main(String args[]) {

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System.out.print("Input a String: ");

String str = scan.nextLine();

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int num = scan.nextInt();

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for(int j=0; j<num; j++) {

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}

}

}

8 0
2 years ago
Ben uses a table that has few columns. He knows about a particular value in the first column and wants to find the corresponding
igor_vitrenko [27]
I'd suggest he uses LOOKUP Function.

You can use the LOOKUP function when you need to look in a single column or row and find a value from the same position in a corresponding column or row. We have a much improved VLOOKUP that can also be used to search one row or column or multiple rows and columns.



4 0
2 years ago
Read 2 more answers
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