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katrin2010 [14]
2 years ago
8

there are 10 less red skittles than orange Skittles in a bag. The orange Skittles are also twice the number of red skittles. Fin

d the number of red and orange Skittles in the bag.
Mathematics
2 answers:
masya89 [10]2 years ago
6 0
There are 20 orange skittles and 10 red skittles since 10 20 is 2 Times more than 10.
Lunna [17]2 years ago
5 0

Answer:  there are 20 orange skittles and 10 red skittles in the bag.

Explanation:

Since we have given that

Let the number of red skittles be x

Let the number of orange skittles be 2x

According to question,

2x-x=10\\x=10

So, there are 10 red skittles in the bag and

The number of orange skittles in the bag is given by

2x=2\times 10=20

Hence, there are 20 orange skittles and 10 red skittles in the bag.

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omeli [17]

18 buckets would be the answer.


7 0
2 years ago
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A feather blew out of a bird nest 10 feet in the air. It drifted to the ground at a constant rate of 2 feet per second. Write an
bonufazy [111]
The answer would be 10/2=5
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1 year ago
An urn contains two blue balls (denoted B1 and B2) and three white balls (denoted W1, W2, and W3). One ball is drawn, its color
alekssr [168]

Answer:

(a) Shown below.

(b) The probability that the first ball drawn is blue is 0.40.

(c) The probability that only white balls are drawn is 0.36.

Step-by-step explanation:

The balls in the urn are as follows:

Blue balls: B₁ and B₂

White balls: W₁, W₂ and W₃

It is provided that two balls are drawn from the urn, with replacement, and their color is recorded.

(a)

The possible outcomes of selecting two balls are as follows:

B₁B₁          B₂B₁          W₁B₁          W₂B₁          W₃B₁

B₁B₂         B₂B₂          W₁B₂         W₂B₂          W₃B₂

B₁W₁         B₂W₁         W₁W₁         W₂W₁         W₃W₁

B₁W₂        B₂W₂         W₁W₂        W₂W₂         W₃W₂

B₁W₃        B₂W₃         W₁W₃        W₂W₃         W₃W₃

There are a total of N = 25 possible outcomes.

(b)

The sample space for selecting a blue ball first is:

S = {B₁B₁, B₁B₂, B₁W₁, B₁W₂, B₁W₃, B₂B₁, B₂B₂, B₂W₁, B₂W₂, B₂W₃}

n (S) = 10

Compute the probability that the first ball drawn is blue as follows:

P(\text{First ball is Blue})=\frac{n(S)}{N}=\frac{10}{25}=0.40

Thus, the probability that the first ball drawn is blue is 0.40.

(c)

The sample space for selecting only white balls is:

X = {W₁W₁, W₂W₁, W₃W₁, W₁W₂, W₂W₂, W₃W₂, W₁W₃, W₂W₃, W₃W₃}

n (X) = 9

Compute the probability that only white balls are drawn as follows:

P(\text{Only White balls})=\frac{n(X)}{N}=\frac{9}{25}=0.36

Thus, the probability that only white balls are drawn is 0.36.

4 0
2 years ago
Marilyn has 10 caramels, 12 mints, and 14 bars of dark chocolate in a bag. She picks three items from the bag without replacemen
Gemiola [76]
10+12+14 = 36

12/36 x 11/35 x 14/34 = 11/255

There's your answer.
3 0
2 years ago
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M<2=34 find m<4 and explain how you know
Naily [24]

Angle 4 equals 34 degrees since angle 2 and 4 are opposite angles and opposite angles are congruent

6 0
2 years ago
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