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kirill115 [55]
2 years ago
15

If tommy rode his bike 4.3 miles a day, 3 days a week for 5 years delivering news papers and he dropped 22.7 newspapers every 1/

4 mile. How many newspapers did tommy drop?
Mathematics
1 answer:
geniusboy [140]2 years ago
6 0

Answer:

277 848 newspapers.

Step-by-step explanation:

Find out how much newspaper he drops for 4.3 miles.

1/4 = 0.25

4.3 miles ÷ 0.25 = 17.2

= 17

17 x 22.7 = 385.9

(Newspapers be dropped a day)

1 week of dropping newspapers = 385.9 x 3 = 1157.7

1 month of dropping newspapers = 1157.7 x 4 =

4630.8

1 year = 12 months

5 years = 12 x 5 = 60 months.

5 years/60 months of dropping newspapers = 4630.8 x 60 = 277 848

Tommy dropped 277 848 newspapers.

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a homeowner wants to carpet two rooms that each measure 12 ft by 15 ft. how many square yards of carpet should be ordered
Lelu [443]

3 feet = 1 yard

12/3 =4

15/3 = 5

4*5 = 20 square yards per room

20*2 = 40 square yards total

7 0
2 years ago
A quality control engineer at a potato chip company tests the bag filling machine by weighing bags of potato chips. Not every ba
Ahat [919]

Answer:

z=\frac{0.21 -0.15}{\sqrt{\frac{0.15(1-0.15)}{100}}}=1.68  

Step-by-step explanation:

Information provided

n=100 represent the random sample taken

X=21 represent the number of bags overfilled

\hat p=\frac{21}{100}=0.21 estimated proportion of overfilled bags

p_o=0.15 is the value that we want to test

z would represent the statistic

Hypothesis

We need to conduct a hypothesis in order to test if the true proportion of overfilled bags is higher than 0.15.:  

Null hypothesis:p =0.7  

Alternative hypothesis:p > 0.15  

The statistic for this case is:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

And replacing the info given we got:

z=\frac{0.21 -0.15}{\sqrt{\frac{0.15(1-0.15)}{100}}}=1.68  

5 0
2 years ago
Quadrilateral ABCD is located at A(-2,2), B(-2,4), C(2,4), and D(2,2). The Quadrilateral is then transformed using the rule (x +
Mice21 [21]

These should help!! The corresponding vertices make a rectangular prism:)

8 0
2 years ago
Manuel painted 0.75 of a rectangular banner green. After the paint dried, he painted 0.6 of the green area orange. What part of
NNADVOKAT [17]

Answer:

0.45 part of the banner is painted orange

Step-by-step explanation:

portion of rectangular banner painted green = 0.75

Portion of green painted part which is now painted orange = 0.60

Hence we can say that

0.6 part out of 0.75 part of total banner is painted orange

mathematically it is

0.6 * 0.75 = 0.45

Thus 0.45 part of banner is painted orange .

6 0
2 years ago
A 92.0 kg football player at 6.50 m/s North collides with an 85.0 kg football player running at 6.00 m/s south. The 92.0 kg foot
s2008m [1.1K]

Answer:

-1.13 m/s

Step-by-step explanation:

Parameters given:

Mass of first footballer, M = 92 kg

Initial velocity of first footballer, U = 6.5 m/s (taking North to be the +ve y axis)

Mass of second footballer, m = 85 kg

Initial velocity of second footballer, u = -6.0 m/s (taking South to be the -ve y axis)

Final velocity of first footballer, V = 2.0 m/s

We need to find the final velocity of the second football (v)

Applying the principle of conservation of momentum, we have that, in a system:

Total Initial Momentum = Total Final Momentum

(M * U) + (m * u) = (M * V) + (m * v)

(92 * 6.5) + (85 * -6) = (92 * 2) + (85 * v)

598 - 510 = 184 + 85v

88 = 184 + 85v

88 - 184 = 85v

-96 = 85v

=> v = -96 / 85

v = -1.13 m/s

The final velocity of the 85 kg player is -1.13 m/s i.e 1.13 m/s South

5 0
2 years ago
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