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jeka94
2 years ago
4

amita decides that she wants the molds to have a square base. how many of the possible molds can she use

Mathematics
1 answer:
iVinArrow [24]2 years ago
6 0
<span>Amita decides that she wants the molds to have a square base. how many of the possible molds can she use? Amita can use "2 Molds." The rectangular prism has a volume of 28 cubic centimeters. Since it is rectangular in shape, and she want to have a square base, the posible mold that she can use is only 2.</span>
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Point P partitions the directed segment from A to B into a 1:3 ratio. Q partitions the directed segment from B to A into a 1:3 r
olga2289 [7]

Answer:

c)No, P is the distance from A to B, and Q is the distance from B to A.

Step-by-step explanation:

Point P partitions the directed segment from A to B into a 1:3 ratio.

Ratio is 1:3

So AP is 1  and PB is 3

Q partitions the directed segment from B to A into a 1:3 ratio.

Ratio is 1:3

So BQ is 1  and QA is 3.

That is AQ= 3  and BQ= 1

The ratio of Q and P varies

AP =1  and AQ=3

So P  and Q  are not at the same point.

Because P is the distance from A  to B  and Q is the distance from B to A



6 0
2 years ago
Read 2 more answers
Suppose a1=12−12,a2=23−13,a3=34−14,a4=45−15,a5=56−16. a) Find an explicit formula for an: . b) Determine whether the sequence is
lorasvet [3.4K]

I'm going to assume you meant to write fractions (because if a_n are all non-negative integers, the series would clearly diverge), so that

a_1=\dfrac12-\dfrac12

a_2=\dfrac23-\dfrac13

a_3=\dfrac34-\dfrac14

and so on.

a. If the pattern continues as above, we would have the general term

a_n=\dfrac n{n+1}-\dfrac1{n+1}=\dfrac{n-1}{n+1}

b. Note that we can write a_n as

a_n=\dfrac{n-1}{n+1}=\dfrac{n+1-2}{n+1}=1-\dfrac2{n+1}

The series diverges by comparison to the divergent series

\displaystyle\sum_{n=1}^\infty\frac1n

4 0
2 years ago
Unit 4: Lesson 9: Parallel and Perpendicular Lines Unit Test Parallel and Perpendicular Lines does anyone have the answers for t
Nookie1986 [14]
What test is this question from?
7 0
2 years ago
There are 360 people in my school. 15 take calculus, physics, and chemistry, and 15 don't take any of them. 180 take calculus. T
lesantik [10]

Answer:

150 students take physics.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that take calculus.

-The set B represents the students that take physics

-The set C represents the students that take chemistry.

-The set D represents the students that do not take any of them.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that take only calculus, A \cap B is the number of students that take both calculus and physics, A \cap C is the number of students that take both calculus and chemistry and A \cap B \cap C is the number of students that take calculus, physics and chemistry.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C), D

There are 360 people in my school. This means that:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) + D = 360

The problem states that:

15 take calculus, physics, and chemistry, so:

A \cap B \cap C = 15

15 don't take any of them, so:

D = 15

75 take both calculus and chemistry, so:

A \cap C = 75

75 take both physics and chemistry, so:

B \cap C = 75

30 take both physics and calculus, so:

A \cap B = 30

Solution:

The problem states that 180 take calculus. So

a + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 180

a + 30 + 75 + 15 = 180

a = 180 - 120

a = 60

Twice as many students take chemistry as take physics:

It means that: C = 2B

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

B = b + 75 + 30 + 15

B = b + 120

-------------------------------

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

C = c + 75 + 75 + 15

C = c + 165

----------------------------------

Our interest is the number of student that take physics. We have to find B. For this we need to find b. We can write c as a function o b, and then replacing it in the equations that sums all the subsets.

C = 2B

c + 165 = 2(b+120)

c = 2b + 240 - 165

c = 2b + 75

The equation that sums all the subsets is:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) + D = 360

60 + b + 2b + 75 + 30 + 75 + 15 + 15 = 360

3b + 270 = 360

3b = 90

b = \frac{90}{3}

b = 30

30 students take only physics.

The number of student that take physics is:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

B = b + 75 + 30 + 15

B = 30 + 120

B = 150

150 students take physics.

6 0
2 years ago
Suppose that a Coke/Pepsi survey was conducted of 400 randomly selected individuals from Gainesville. Two hundred people selecte
AlexFokin [52]

Answer:

A. There are not 15 successes and 15 failures. A confidence interval can be computed by adding 2 successes and 2 failures.

6 0
2 years ago
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