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poizon [28]
2 years ago
13

Jeff lives 12 miles east of Stan. Jeff lives 16 miles north of Wei. What is the shortest distance that Stan and Wei can live fro

m each other?
Mathematics
1 answer:
Greeley [361]2 years ago
7 0
|  \
|     \ 
| 16  \
|         \
|______\
 12

Envision this as a right triangle, with one leg of 12 miles, and the other 16 miles. Solve using the Pythagorean Theorem a²+b²=c²:

12²+16²=c²
400 = c²
20=c...they live at least 20 miles from each other.

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What is the diameter of a hemisphere with a volume of 651 m^3, to the nearest tenth<br> of a meter?
Sphinxa [80]

Answer: 13.5 m, hope this helps :)

5 0
2 years ago
Five friends bake ginger bread and subsequently meet up for a tasting session. Each one gives one of his ginger
GenaCL600 [577]

Answer:

The five friends had 10 fingers to start with; one had two each

Step-by-step explanation:

The statement says each gave one of not all of his ginger in the toasting session.

4 0
2 years ago
In a USA TODAY/Gallup Poll, respondents favored Barack Obama over Mitt Romney in terms of likeability, 61% to 32% (Los Angeles T
dybincka [34]

Answer:

a) percentage of respondents that favored neither Obama nor Romney in terms of likeability = 7%

b) For a given survey of 500, the number of respondents that favored Obama than Romney is 145.

Step-by-step explanation:

Given that none of those surveyed can favour the two candidates at the same time,

n(Universal set) = n(U) = 100%

n(Obama) = n(O) = 61%

n(Romney) = n(R) = 32%

n(That favour Obama and Romney) = n(O n R) = 0%

To calculate for the number that favour neither of the candidates

n(O' n R')

n(U) = n(O) + n(R) + n(O n R) + n(O' n R')

100 = 61 + 32 + 0 + n(O' n R')

n(O' n R') = 100 - 93 = 7%

b) For a given survey of 500, how many more respondents favored Obama than Romney?

Number of those surveyed that favour Obama = 61% of 500 = 305

Number of those surveyed that favour Romney = 32% of 500 = 160

Difference = 305 - 160 = 145

5 0
2 years ago
Complete the table of inputs and outputs for the given function g(x)=3-8x.
Andreas93 [3]

Answer:

The answers to your questions are given below.

Step-by-step explanation:

From the question given above,

g(x) = 3 – 8x

Thus, we can complete the table given in question above as follow:

1. Determination of x

g(x) = 0

x =?

g(x) = 3 – 8x

0 = 3 – 8x

Collect like terms

0 – 3 = – 8x

– 3 = – 8x

Divide both side by –8

x = – 3 / –8

x = 3/8

2. Determination of g(x)

x = 0

g(x) =.?

g(x) = 3 – 8x

g(x) = 3 – 8(0)

g(x) = 3 – 0

g(x) = 3

3. Determination of x

g(x) = – 5

x =?

g(x) = 3 – 8x

– 5 = 3 – 8x

Collect like terms

– 5 – 3 = – 8x

– 8 = – 8x

Divide both side by – 8

x = – 8 / – 8

x = 1

4. Determination of g(x)

x = 3

g(x) =.?

g(x) = 3 – 8x

g(x) = 3 – 8(3)

g(x) = 3 – 24

g(x) = – 21

Summary

x >>>>>>>>>>>>>>> g(x)

3/8 >>>>>>>>>>>>> 0

0 >>>>>>>>>>>>>>> 3

1 >>>>>>>>>>>>>>>> – 5

3 >>>>>>>>>>>>>>> – 21

6 0
2 years ago
The function f(x) = –10(x)(x – 4) represents the approximate height of a projectile launched from the ground into the air with a
sineoko [7]
The height of the project becomes zero when it hits the ground which is also the total time at which the projectile stays in the air. Equating the function to zero:
-10(x)(x - 4) = 0
The roots of this quadratic equation are:
x = 0, and x=4

Therefore, the projectile stays in the air for
4 seconds

4 0
2 years ago
Read 2 more answers
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