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2 years ago

What are potential roots of p(x) = x4 + 22x2 – 16x – 12

2 answers:

8 0

Simplify 22\times 222×2 to 4444
{x}^{4}+44-16x-12x4+44−16x−12Collect like terms
{x}^{4}+(44-12)-16xx4+(44−12)−16x Simplify{x}^{4}+32-16xx4+32−16x

rjkz [21]2 years ago

4 0

Answer:

±1, ±2, ±3, ±4, ±6 and ±12

Step-by-step explanation:

The potential roots are obtained as following:

potential roots = factors of the constant term / factors of leading coefficient

The constant term is -12, its factors are ±1, ±2, ±3, ±4, ±6 and ±12

The leading coefficient is 1, its factors are ±1

Therefore the potential roots are ±1, ±2, ±3, ±4, ±6 and ±12

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