We are given that we have $25 to pay for 6 fishing lures.
We can make an equality for this as follows:
Suppose price of one fishing lure is x dollars.
So we will use unitary method to find price of 6 fishing lures.
Price of 6 fishing lures = 6 * ( price of one fishing lure) = 6* x = 6x
Now we only have 25 dollars with us, so the price of 6 fishing lures has to be less than or equal to 25 dollars.
So creating an inequality,
Now in order to find price for one fishing lure, we have to solve this for x.
Dividing both sides by 6 we have,
Converting to decimal,
Answer : The price of one fishing lure must be less than or equal to $4.167
Step-by-step explanation:
x-the initial number of coconuts
x=3y+1
2y=3z+1
2z=3×7+1=>z=11=>y=17=>x=52
x^4 + 6x^3 + 33x^2 + 150x + 200
x^4 + 2x^3 + 4x^3 + 8x^2 + 25x^2 + 50x + 100x + 200
x^3 x (x + 2) + 4x^2 x (x + 2) + 25x x (x+2) + 100 (x + 2)
(x + 2) x (x^3 + 4x^2 + 25x + 100)
(x + 2) x (x^2 x (x + 4) + 25 (x + 4))
solution : (x + 2) x (x + 4) x (x^2 + 25)
In geometry, it is always advantageous to draw a diagram from the given information in order to visualize the problem in the context of the given.
A figure has been drawn to define the vertices and intersections.
The given lengths are also noted.
From the properties of a kite, the diagonals intersect at right angles, resulting in four right triangles.
Since we know two of the sides of each of the right triangles, we can calculate their heights which in turn are the segments which make up the other diagonal.
From triangle A F G, we use Pythagoras theorem to find
h1=A F=sqrt(20*20-12*12)=sqrt(256)=16
From triangle DFG, we use Pythagoras theorem to find
h2=DF=sqrt(13*13-12*12)=sqrt(25) = 5
So the length of the other diagonal equals 16+5=21 cm
1/2 because 5/9 is equivalent to 10/18. Half of 18 is 9 and 10 is close to 9 so the nearest benchmark fraction you should round to is 1/2. Hope this helps you!
