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Ostrovityanka [42]
2 years ago
10

Juan analyzes the amount of radioactive material remaining in a medical waste container over time. He writes the function f(x) =

10(0.98)x to represent the amount of radioactive material that will remain after x hours in the container. Rounded to the nearest tenth, how much radioactive material will remain after 10 hours?
Mathematics
2 answers:
serious [3.7K]2 years ago
6 0

Answer:

8.2 units of radioactive material will remain after 10 hours

Step-by-step explanation:

Given : f(x)=10(0.98)^{x}

To Find : , how much radioactive material will remain after 10 hours?

Solution :

Since we are given a function that represents the amount of radioactive material remaining in a medical waste container over time.

f(x)=10(0.98)^{x}

Where x denoted hours

Since we are asked to find the amount of radioactive after 10 hours .

So, put x = 10 in the given function

f(10)=10(0.98)^{10}

f(10)=10*0.8170

f(10)=8.170

Thus f(10)=8.17 ≈ 8.2

Hence 8.2 units of radioactive material will remain after 10 hours

Sloan [31]2 years ago
5 0
For radioactive decay, the amount should decrease over time. Given the function:
f(x)=10(0.98)^x
We substitute the time of x = 10 hours:
f(10)=10(0.98)^{10} \\ f(10) = 8.17
Therefore 8.2 units will remain after 10 hours.

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A bank says you can double your money in 8 years if you put $2,000 In a simple interest account. what annual interest rate does
Monica [59]
A = P*r*t
A = overall value
P = principal (initial value)
r = annual interest
t = time (in years)

Plug in what we have:
4000 = 2000*r*8
Simplify:
0.25 = r
The annual interest is 25%
5 0
2 years ago
Read 2 more answers
A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time).
likoan [24]

Answer:

(a). 72.9%.

(b). 13.6 hr.

Step-by-step explanation:

So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;

=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "

=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"

So, we will be making use of the Crawford learning curve model.

T(7) + 10 = T (17) = 30 min.

T(7) = T1(7)^b = 45.

T(17 ) = T1(17)^b = 30.

(T1) = 45/7^b = 30/17^b.

45/30 = 7^b/17^b = (7/17)^b.

1.5 = (0.41177)^b.

ln 1.5 = b ln 0.41177.

0.40547 = -0.8873 b.

b = - 0.45696.

=> 2^ -0.45696 = 0.7285.

= 72.9%.

(b). T1= 45/7^ - 045696 = 109.5 hr.

V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .

V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .

= 815.7 min .

= 13.595 hr.

8 0
2 years ago
I met this hella weird cryptic dude who interviewed me and gave me this puzzle. Solve it within 12 hours and ill let you know wh
Elena-2011 [213]

no cheating thanks <3

6 0
2 years ago
Part B
Troyanec [42]

Answer:

Part A) The length of a straight line between the school and the Fire Station is 4.6\ miles

Part B) The length of a straight line between the school and the hospital is 2.1\ miles

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

Let

The positive x-coordinates ----> East

The positive y-coordinates ----> North

The negative x-coordinates ----> West

The negative y-coordinates ----> South

take the point A (0,0) as the Middle School (reference point)

Part A) we have

Town Hall is located 4.3 miles directly east of the Middle School

so

The coordinates of Town Hall are B(4.3,0)

The Fire Station is located 1.7 miles directly North of Town Hall

so

The coordinates of Fire Station are C(4.3,1.7)

What is the length of a straight line between the school and the Fire Station?

Remember that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(0,0) and C(4.3,1.7)

substitute

d=\sqrt{(1.7-0)^{2}+(4.3-0)^{2}}

d=\sqrt{(1.7)^{2}+(4.3)^{2}}

d=4.6\ miles

Part B) we have that

The hospital is 3.1 miles west of the fire station

so

The coordinates of the hospital are D(4.3-3.1,1.7)

D(1.2,1.7)

What is the length of a straight line between the school and the hospital?

Remember that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(0,0) and D(1.2,1.7)

substitute

d=\sqrt{(1.7-0)^{2}+(1.2-0)^{2}}

d=\sqrt{(1.7)^{2}+(1.2)^{2}}

d=2.1\ miles

7 0
2 years ago
Solve for w. 5w + 9z = 2z + 3w w = w equals negative StartFraction 7 Over 2 EndFraction z.Z w = w equals negative StartFraction
TEA [102]

Answer:

w = -7z/2

Step-by-step explanation:

We need to solve for w in terms of z.

The equation given is:

5w + 9z = 2z + 3w

Collect like terms:

5w - 3w = 2z - 9z

2w = -7z

w = -7z/2

5 0
2 years ago
Read 2 more answers
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