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kodGreya [7K]
2 years ago
13

When you use the distance formula, you are building a(n) _____ whose hypotenuse connects two given points.

Mathematics
2 answers:
Alja [10]2 years ago
4 0
When you use the distance formula, you are building a(n) right triangle whose hypotenuse connects two given points.
tekilochka [14]2 years ago
3 0
<span>When you use the distance formula, y</span>ou are building a right triangle. 

I hope this helps!
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Which of the following functions gives the radius, r(v), of a conical artifact that is 20 inches tall as a function of its volum
irinina [24]
<h3><u>Radius as function of volume is:</u></h3>

r(v) = \sqrt{\frac{3v}{20 \pi }}\ inches

<em><u>Solution:</u></em>

<em><u>The volume of cone is given as</u></em>:

v = \frac{1}{3}\pi r^{2} h

Where,

r is the radius

h is the height

From given,

height = 20 inches

From formula,

v = \frac{1}{3}\pi r^{2} h

Rearrange , so that r is alone in left side of equation

3v = \pi r^2 h\\\\\pi r^2 h = 3v\\\\r^2 = \frac{3v}{\pi h}\\\\Take\ square\ root\ on\ both\ sides\\\\r = \sqrt{\frac{3v}{\pi h}}

Substitute h = 20

r = \sqrt{\frac{3v}{20 \pi }}

Thus, radius as function of volume is:

r(v) = \sqrt{\frac{3v}{20 \pi }}\ inches

4 0
2 years ago
A teacher wants to see if a new unit on factoring is helping students learn. She has five randomly selected students take a pre-
sergiy2304 [10]

Answer:

The <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.

Step-by-step explanation:

The confidence interval formula for mean difference for a paired data is as follows:

CI=\bar x_{d}\pm t_{\alpha/2, (n-1)}\times \frac{s_{d}}{\sqrt{n}}

Here,

\bar x_{d} = sample mean of the difference,

s_{d} = sample standard deviation of the difference,

<em>n </em>= sample size (both samples are of same size).

t_{\alpha/2, (n-1)} = critical value of <em>t</em>

(<em>n</em> - 1) = degrees of freedom

The information provided is:

<em>n</em> = 5

Confidence level = 95%

The critical value of <em>t</em> is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (5-1)}

               =t_{0.025, 4}

               =2.776

*Use a <em>t</em>-table for the critical value of <em>t</em>.

Thus, the <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.

4 0
2 years ago
share one tip or suggestion on how others can represent real-life situations using rational functions​
posledela

Answer:

The answer is below

Step-by-step explanation:

There are various tips or suggestions on how others can represent real-life situations using rational functions​, one of them is the application of a work problem formula.

By using the work problem formula, one can measure the time it will take different people working at different speeds to complete the work. With the formula w =r*t. Where w = work done, r = rate of work donee, and t = time

7 0
2 years ago
Which choice describes the value of m when –5(m + 1) ≤ 23?
RSB [31]

Answer:

m\leq-5.6

Step-by-step explanation:

-5m-5\leq23

-5m\leq28

m\leq-5.6

6 0
2 years ago
Read 2 more answers
Leon needs to save more than $350 to buy a new bike. He has $130 saved so far, and he plans to save $20 each week until he has e
zlopas [31]

He must save for 12 or more weeks.


4 0
2 years ago
Read 2 more answers
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