Answer:
Based on selecting a sample of 300 computers The probability questions are follows
1. . What is the probability that no computer needs service within the warranty period?
2 . What is the probability that more than half of the computers that are sampled will need warranty period?
3. What is the expected number of computers fail before the warranty period?
Answer:
Gas Pumping Stattion
Explanation:
I think this is the answer.....
Hope this helps lmo
Answer: A) Give and explain counter-arguments against the arguments for each side.Note: the "counter-arguments" you are asked to give should oppose or answer the arguments on the other side as directly and convincingly as possible. They should not be simply unrelated arguments on the opposite side of the issue.
Explanation: When is talking about security is important to have different views, firstable you need to establish which are going to be your claims, premises or arguments, once you got it is important to search for information which can support your ideas, and once you have found it, counter-arguments are necessary to understand which are your weakest point, you need to know your counter-arguments and how people are likely to attack you, once you know the weak part of your speech you can defend it.
Answer:
The invoice price for the bond is $1,060.38
Explanation:
Given the following:
PV= Par value = $1,000
,
CV= Clean Price = $1,049
Coupon Rate per annum = 6.83%
To calculate the Semiannual Coupon Rate= Coupon Rate per annum/2= 3.415%
To calculate Semiannual Coupon= Semiannual Coupon Rate*PV
= 3.415% * $1,000 = $34.15
With an interest accured over 2 months, we calculate it thus:
Accrued Interest = $34.15 * 2/6
= $11.38
To calculate Invoice price:
Invoice Price = CP + Accrued Interest
Invoice Price = $1,049.00 + $11.38
Invoice Price = $1,060.38
Answer:
C.Greater than 0.75
Explanation:
Given
Cu = $120
Co = $360
We know Probability P <= Cu/(Cu + Co)
P = 120/(120 + 360)
= 120/480
= 0.25
P is the probability of unit is will not sold and 1-p is the probability of unit that will sold
1 - p = 1 - 0.25
= 0.75
probability of the last unit being sold should be greater than 0.75
