All categories

2 years ago

Which formula can be used to calculate the horizontal displacement not of a horizontally launched projectile

1 answer:

8 0

If you are looking to get an object up the highest, shoot it straight up. If you want to go for a specific horizontal displacement, use the range equation. R = v2sin(twice the launch angle)/ g. g is the gravitaional constant, 9.8 meters per second. Use degrees for the angle. v is the launch velocity. R is the horizontal displacement. This formula only works if your start altitude and end altitude are the same, i.e. you must shoot over a level field. it depends on the gravitational force of attraction of earth and air resistance. if we are neglecting air resistance, the max.horizontal distance is according to this formulae, V0/2 * sin (2theta) where V0 is the initial velocity theta is the angle with x axis and the projection. There are a number of ways that you could find a horizontally displaced object. You could for example just look.

You might be interested in

Jill puts her face in front of a convex mirror, 18 cm from the focal point of the mirror. If the focal point is located 12 cm fr

Bumek [7]

A. 4 cm behind the mirror
 For any mirror, sosi=f^2. Therefore, by plugging in the values, you get 18si=144. 144/18 = 8, so si=8
 The focal point is located 12 cm from the mirror, and si is the distance of the image from the focal point, so the image is 4 cm from the mirror. The mirror is convex, so then the focal point and the image are both behind the mirror.

5 0

2 years ago

Read 2 more answers

The weight of a 72.0 kg astronaut on the Moon, where g = 1.63 m/s2 is (5 points) Select one: a. 112 N b. 117 N c. 135 N d. 156 N

kipiarov [429]

Answer: The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

Explanation:

Mass of the astronaut on the moon , m= 72 kg

Acceleration due to gravity on moon,g = 1.63 $m/s^2$

According to Newton second law of motion: F = ma

This will changes to = Weight = mass × g

$Weight=72 kg\times 1.63m/s^2=117.36 N$

The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

7 0

2 years ago

Read 2 more answers

Four students were loading boxes of food collected during a food drive. The force that each student exerted while lifting and th

Fudgin [204]

Answer:

it is B

Explanation:

Edge2020

7 0

2 years ago

Read 2 more answers

The mass of Venus is 81.5% that of the earth, and its radius is 94.9% that of the earth. If a rock weighs 75.0 N on earth, compu

IgorLugansk [536]

Answer:

g = 0.905 gE

W = 67.9 N

Explanation:

given data

mass of Venus mv = 81.5% = 0.815

radius Rv = 94.9% = 0.949

weighs W = 75.0 N

solution

we apply here acceleration due to gravity at earth surface that is

g = $\frac{Gm}{R^2}$ = 9.80 m/s² ............1

g = $\frac{G(0.815)}{0.949R^2}$

g = 0.905 gE

and

W = m gv

W = 0.905 m gE

W = 0.905 × 75

W = 67.9 N

7 0

2 years ago

Construction of a solar power plant is proposed for a desert area near a school. A student has hypothesized that the shade cast

hjlf

Answer:

4. The direct sunlight received by creosote bush in the desert area (in kWh/m2) during a 12 month period

Explanation:

The creosote bush depends on sunlight to produce the food they require through photosynthesis. The shade from the solar panels would reduce the amount of sunlight that the bush receives. This would increase the mortality of the bush.

In order to test the hypothesis the student must record the direct sunlight received by creosote bush in the desert area (in kWh/m2) during a 12 month period. If the plants receive sunlight less than the above amount the plants should start dying. If not then the hypothesis is false.

Hence, the answer is 4. The direct sunlight received by creosote bush in the desert area (in kWh/m2) during a 12 month period.

4 0

2 years ago