Let us consider each statement separately. A zygote is the result of the fusion of two gametes (reproductive cells) and thus only appears in sexual reproduction. For the same reason, E) is wrong; meiosis is a step in the making of gametes and again, a plant that reproduces asexually does not produce gametes. B) is also wrong since (healthy) members of the same species have the same number of chromosomes. The leaf cells of the daughter plant will have 24 chromosomes. The only case where this would not hold, is the case of sexual reproduction, where the gametes of the new organism have half the chromosomes of the ancestor organisms. Hence, C and D are correct. We have already justified D. As far as C is concerned, in asexual reproduction we have that every organism passes his whole genome to his offspring and this creates a lot of clones next to each other. Every plant in a garden of a species that reproduces asexually may be genetically identical and some biologists consider them for that reason as the same organism!
Answer:
The answer is- A bundling relationship
Explanation:
Bundling is defined as when a company packages some of their products or services together as a single combined unit, often for a lower price than they would charge the customers if the items are sold independently or separately. This helps to facilitate the convenient sale of products or services from one company.
An example could be if Oral-B decides to sell both their toothpaste and toothbrush together as a single combined unit at a lower price than if selling the toothpaste or toothbrush separately.
BioMark Lifesystems' arrangement with the producer of syringes and test tubes to have diagnostic substances sold to laboratories in a package along with the syringes and tubes is called bundling relationship.
I believe the answer is C, as when the sun is tilted at different angles different places will get different amounts of sunlight.
The answer is; B
If we assume that the allele for black fur is B and that for white fur is b, crossing a homozygous black rabbit with a heterozygous black rabbit, will yield the following results (indicated in the punnet square below);
Genotypically, 50% of the population will be homozygous dominant, while 50% will be heterozygous. However, phenotypically, all offspring will bear black fur because the black fur allele is dominant over the grey allele.
Answer:
Acidosis will interfere more.
Explanation:
The natural ph in jejunum is usual neutral or slightly alkaline so the antibody absorption will not be possible if the medium isn't alkaline.
