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Murrr4er [49]
2 years ago
10

Ten percent of the items produced by a machine are defective. out of 15 items chosen at random, what is the probability that les

s than 3 items will be defective?
Mathematics
1 answer:
sineoko [7]2 years ago
4 0
Quality controla process that evaluates output relative to a standard and takes corrective action when output doesn't meet standardsinspection<span>appraisal of goods and services
-necessary to physically examine some of the goods</span>acceptance samplingDo existing shipments meet predetermined standards?process controlIs the process stable? Future Output Acceptable?inspection<span>How Much to Inspect/How Often
At What points should inspection occur 
Centralized vs. On-site
Attributes vs. Variables</span>where to inspect in the process<span>Raw materials and purchased parts
Finished products
Before a costly operation
Before an irreversible process
Before a covering process</span>centralized labspecial equipment, more favorable testing atmosphere, etcon sitequicker decisions, avoidance of other extraneous factors,etc.attributes<span>characteristics which are present or not present; they are counted
EX: is the top of the bottle cracked or not?</span>variables<span>characteristics which are present in varying degrees; they are measured
EX: diameter of a washer bolt</span>acceptance samplingForm of inspection applied to lots or batches of items before or after a process, to judge conformance with predetermined standardssampling plansPlans that specify lot size, sample size, number of samples, and acceptance/rejection criteriasingle plan<span>one random sample is drawn from the lot and every item in sample is examined.
< c defects; Accept
> c defects; Reject</span>double plan<span>take a second sample if first is inconclusive.
< c1 defects; Accept
> c2 defects; Reject
in second sample:
< c3 defects; Accept
> c3 defects; Reject</span>multiple plan<span>same logic as double-plan except additional samples are drawn until you clearly fall into either the acceptance or rejection category
-Choosing a plan depends on cost and time. cost of analysis vs. cost of drawing sample</span>operating characteristics curve<span>It is generally not optimal to inspect all items so we have to sample some %. The problem is that you can't discriminate perfectly between good and bad lots without 100% inspection.
-An important feature is how well it discriminates between lots of high quality and lots of low quality.
-shows the probability that use of the sampling plan will result in lots with various fraction defectives being accepted</span>acceptance quality level (AQL)the percentage level of defects at which consumers are willing to accept lots as "good" (1-2%)lot tolerance percent defective (LTPD)the upper limit on the percentage of defects that a consumer is willing to acceptconsumers risk (beta)the probability that a lot containing defectives exceeding the LTPD will be accepted
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A standard number cube has 6 sides labeled 1 to 6. apu rolls a standard number cube 30 times. How many times can
Leviafan [203]

Answer:

The expected value of rolling a 5 or 6 is 10.

Step-by-step explanation:

The sample space of rolling a standard number cube is:

S = {1, 2, 3, 4, 5 and 6}

The cube is standard, this implies that each side has an equal probability of landing face-up.

So, the probability of all the six outcomes is same, i.e. \frac{1}{6}.

Now it is provided that Apu rolls the cube <em>n</em> = 30 times.

Let the random variable <em>X</em> represent the value on the face of cube.

The event of rolling a 5 and rolling a 6 are mutually exclusive, i.e. they cannot occur together.

So, P (X = 5 and X = 6) = 0.

Compute the probability of getting a 5 or 6 as follows:

P (X = 5 or X = 6) = P (X = 5) + P (X = 6) - P (X = 5 and X = 6)

                            = P (X = 5) + P (X = 6)

                            =\frac{1}{6}+\frac{1}{6}\\\\=\frac{2}{6}\\\\=\frac{1}{3}

Compute the expected value of rolling a 5 or 6 as follows:

E(X = 5\ \text{or}\ X = 6)=n\times P(X = 5\ \text{or}\ X = 6)

                               =30\times \frac{1}{3}\\\\=10

Thus, the expected value of rolling a 5 or 6 is 10.

8 0
2 years ago
Alex found a new black bean soup recipe that calls for tomatoes and black beans. If tomatoes cost $1.60 per pound and black bean
djverab [1.8K]

Alex can buy at most 4 pounds of tomatoes

Let:

a represent pounds of tomatoes to buy

3a represent pounds of black beans to buy

Total cost of each ingredient that can be bought = number of pounds x price per pound

Tomatoes = a x $1.60 = 1.60a

Black beans = 3a x $1.70 = 5.1a

1.60a + 5.1a = 26.80

Add similar terms

6.7a = 26.80

Divide both sides of the equation by 6.7

a = 4 pounds

A similar question was solved here: brainly.com/question/848628?referrer=searchResults

7 0
2 years ago
Susan is attending a talk at her son's school. There are 8 rows of 10chairs where 54 parents are sitting. Susan notices that eve
kozerog [31]

Answer:

The largest possible number of adjacent empty chairs in a single row is 3

Step-by-step explanation:

The parameters given are;

The number of chairs = 8 × 10 = 80 chairs

The number of parents = 54

Sitting arrangements of parents = Alone or to one other person

Therefore;

The maximum number of parents on a row = 1 + 1 + 0 + 1 + 1 + 0 + 1 + 1 + 0 + 1 = 7

Hence when the rows have the maximum number of parents occupying the seats we have for the 8 rows;

7 + 7 + 7 + 7 + 7 + 7 + 7 + 7 = 56

But there are only 54 parents, therefore, up to the 7th row will have 7 parents while the 8th row will have only 5 parents to make the possible sitting arrangement to be as follows;

7 + 7 + 7 + 7 + 7 + 7 + 7 + 5 = 54

The sitting arrangement for the 8th row is therefore

1 + 1 + 0 + 1 + 1 + 0 + 1 + 0 + 0 + 0

Hence there will be three empty seats in the 8th row making the largest possible number of adjacent empty chairs in a single row = 3.

4 0
2 years ago
There were 8,651 deaths and 14,662 births reported in Hillsborough County in the year 2000. If there were 998,948 people living
alexdok [17]

Crude birth rate is all the time reported per 1000 living people.

To compute for this, the formula is number of births x 1000 divided by the estimated population at midyear. So plugging in the values given:

14,662 x 1000 divided by 994,948

= 14662000 / 994948

= 14.68 per 1000 living people.

7 0
2 years ago
Read 2 more answers
A quality control engineer at a potato chip company tests the bag filling machine by weighing bags of potato chips. Not every ba
Ahat [919]

Answer:

z=\frac{0.21 -0.15}{\sqrt{\frac{0.15(1-0.15)}{100}}}=1.68  

Step-by-step explanation:

Information provided

n=100 represent the random sample taken

X=21 represent the number of bags overfilled

\hat p=\frac{21}{100}=0.21 estimated proportion of overfilled bags

p_o=0.15 is the value that we want to test

z would represent the statistic

Hypothesis

We need to conduct a hypothesis in order to test if the true proportion of overfilled bags is higher than 0.15.:  

Null hypothesis:p =0.7  

Alternative hypothesis:p > 0.15  

The statistic for this case is:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

And replacing the info given we got:

z=\frac{0.21 -0.15}{\sqrt{\frac{0.15(1-0.15)}{100}}}=1.68  

5 0
2 years ago
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