All categories

2 years ago

What is the answer for 5kx+6=7kx solve for x

Mathematics

2 answers:

Bogdan [553]2 years ago

6 0

7kx-5kx=6
2kx=6
x=3/k
All the best

Lera25 [3.4K]2 years ago

5 0

Let's solve for x.5kx+6=7kx
Step 1: Add -7kx to both sides.5kx+6+−7kx=7kx+−7kx−2kx+6=0
Step 2: Add -6 to both sides.−2kx+6+−6=0+−6−2kx=−6
Step 3: Divide both sides by -2k.‌−2kx−2k‌=‌−6−2k‌x=‌3/k

You might be interested in

Question 1 (1 point) The yearly interest payable on a deposit of $250 at 5.5% p.a. simple interest is: A $137.50 B $13.75 C $12.

dlinn [17]

Answer:

B: $13.75

Step-by-step explanation:

5.5% of $250 = $13.75

Therefore, the simple interest is $13.75.

6 0

1 year ago

There were 340,000 cattle placed on feed. Write an equivalent ratio that could be used to find how many of these cattle were bet

lutik1710 [3]

There were 340,000 cattle placed on feed

How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?

Given the fraction of total cattle for 700 - 799 pounds is 2/5

Let x be the number of cattle between 700 - 799 pounds

We make a proportion using the fraction

$\frac{2}{5} = \frac{x}{340,000}$

Cross multiply it and solve for x

340000* 2 = 5x

680000 = 5x

Divide by 5 on both sides

So x= 136,000

There were 136,000 cattle between 700 and 799 pounds

3 0

2 years ago

Read 2 more answers

In a second grade class containing 12 girls and 11 boys, 2 students are selected at random to give out the math papers. what is

MrRissso [65]

12/23 = probability first is a girl
11/22= probability second is a boy
probability of both 132/506
132/506 = 66/253

3 0

2 years ago

Read 2 more answers

The demand function for a type of portable radio is given by the model d=85−6x2, where d is measured in dollars and x is measure

Lostsunrise [7]

Answer:

Part A : The required Profit equation : $\text{Profit}= 60x-6x^3$

Part B : 0.303 million radios the profit became 18 million.

Part C : The graph is attached below.

Step-by-step explanation:

Given : The demand function for a type of portable radio is given by the model $d=85-6x^2$ , where d is measured in dollars and x is measured in millions of units. The production cost is $25.00 per radio.

Note: Given that profit = revenue - costs

Revenue is demand times number sold.

Costs are productions costs per number sold.

To find :

Part A: Write an equation giving profit as a function of x million radios sold.

Solution : Let x be the number of radios.

Revenue is demand times number sold

$\text{Revenue}= x\times (85-6x^2)$

$\text{Revenue}= 85x-6x^3$

Let the cost of x number of radios is 25x.

Profit = Revenue - Costs

$\text{Profit}= 85x-6x^3-25x$

$P(x)= 60x-6x^3$

The required Profit equation : $P(x)= 60x-6x^3$

Part B : The company currently produces 3 million radios and makes a profit of $18,000,000, but would like to scale back production. What lesser number of radios could the company produce to yield the same profit?

Solution : It is shown graphically which is attached in part c

When we scale back production we get that,

When we sold 0.303 million radios the profit became 18 million.

Part C : Give a graph for the profit and label the parts of the graph.

The graph is attached below which shows the profitable radios points.