△RST is dilated with the rule DT,1/3 (x, y), where the center of dilation is T(3, –2).
The distance between the x-coordinates of R and T is 3 .
The distance between the y-coordinates of R and T is 6.
R' is 1 unit left,2 units up from T, so the coordinates of R' are (2,0)
Inscribe triangle RST in the square with dimensions 4×4, as shown in the figure.
from the area of this square, 4*4=16, we remove the triangles with dimensions
3×4, 2×1 and 2×4, whose side lengths are shown in the figure, and we are left with the area of triangle RST.
so

units squared
similarly,

units squared
Thus, the areas are equal.
Answer:
dx/dt = 0,04 m/sec
Step-by-step explanation:
Area of the circle is:
A(c) =π*x² where x is a radius of the circle
Applying differentiation in relation to time we get:
dA(c)/dt = π*2*x* dx/dt
In this equation we know:
dA(c)/dt = 0,5 m²/sec
And are looking for dx/dt then
0,5 = 2*π*x*dx/dt when the area of the sheet is 12 m² (1)
When A(c) = 12 m² x = ??
A(c) = 12 = π*x² ⇒ 12 = 3.14* x² ⇒ 12/3.14 = x²
x² = 3,82 ⇒ x = √3,82 ⇒ x = 1,954 m
Finally plugging ths value in equation (1)
0,5 = 6,28*1,954*dx/dt
dx/dt = 0,5 /12.28
dx/dt = 0,04 m/sec
Answer:
5.75x10^11
Step-by-step explanation:
quotient of 2,300 and (0.4x10^-8) is
2,300 ÷ (0.4x10^-8)
2300 = 2.3x10^3
We now have
2.3x10^3 / 0.4x10^-8
= (2.3/0.4) x ( 10^(3 - (-8))
= 5.75 x (10^(3+8))
= 5.75 x (10^11)
= 5.75x10^11
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