Firstly, start by doing Punnett squares for each of the characteristics. Attached are the three Punnet squares, made by me, as they should look in end.
For each of the Punnet squares, one characteristic each, we find that half of the offspring will be heterozygous for that characteristic.
Therefore, according to the product rule, you should now multiply the quantity of heterozygous for each characteristic and then obtain the total part of the offspring that's fully heterozygous.

Ss×

Ll×

Rr=

SsLlRr
Total offspring×

=10
There is 10 plants in the total offspring that are heterozygous for all the considered three genes.
They will shrink , that is your answer.
I found the attached image on the internet and I believe it has the tiles referred to on the question.
As we can see on the image, the A-site, P-site, and E-site are represented. The A-site is occupied by the tRNA linked to the growing peptide chain. The P-site is the one occupied by the tRNA that works accepting the growing protein for peptide bond formation.
Firstly, the protein is formed, it is the
first tile from the left.
Then, the
first tile from the right is where the Leu is formed.
On the
second tile from the right the Leu is then added to the protein.
The process is then repeated again as there are two cycles of elongation adding a Leu in each of them:
third tile from the right,
third tile from the left,
second tile from the left.
Answer: Aminos, Phosphates and Carbonyls
Hope this helps you!