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kompoz [17]
2 years ago
13

Faith started last week with $1,100 in her checking account. During the week, she wrote the checks below.

Mathematics
2 answers:
quester [9]2 years ago
6 0

Answer:

the correct answer is A

Step-by-step explanation:


Sunny_sXe [5.5K]2 years ago
5 0

Answer:

A- Faith did a good job; everything is correct.

Step-by-step explanation:

Her final balence is correct, and she organized her check register correctly.

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LiRa [457]
The answer would be A.
if he lost 8 seconds off of 3 pit stops that means he lost 24 seconds. if he can’t 10 seconds for the 2 he made, he gained 20. so therefore, he is only 4 seconds behind the leader. I hope this helps :)
8 0
2 years ago
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On a certain​ route, an airline carries 7000 passengers per​ month, each paying ​$30. A market survey indicates that for each​ $
KengaRu [80]

Answer:

The ticket price that maximizes revenue is $50.

The maximum monthly revenue is $250,000.

Step-by-step explanation:

We have to write a function that describes the revenue of the airline.

We know one point of this function: when the price is $30, the amount of passengers is 7000.

We also know that for an increase of $1 in the ticket price, the amount of passengers will decrease by 100.

Then, we can write the revenue as the multiplication of price and passengers:

R=p\cdot N=(30+x)(7000-x)

where x is the variation in the price of the ticket.

Then, if we derive R in function of x, and equal to 0, we will have the value of x that maximizes the revenue.

R(x)=(30+x)(7000-100x)=30\cdot7000-30\cdot100x+7000x-100x^2\\\\R(x)=-100x^2+(7000-3000)x+210000\\\\R(x)=-100x^2+4000x+210000\\\\\\\dfrac{dR}{dx}=100(-2x)+4000=0\\\\\\200x=4000\\\\x=4000/200=20

We know that the increment in price (from the $30 level) that maximizes the revenue is $20, so the price should be:

p=30+x=30+20=50

The maximum monthly revenue is:

R(x)=(30+x)(7000-100x)\\\\R(20)=(30+20)(7000-100\cdot20)\\\\R(20)=50\cdot5000\\\\R(20)=250000

3 0
2 years ago
Calculate a23 for the product of the following matrices
s344n2d4d5 [400]

If A is the matrix product

A=\underbrace{\begin{pmatrix}1&2\\4&3\end{pmatrix}}_{M_1}\underbrace{\begin{pmatrix}6&1&5\\7&3&4\end{pmatrix}}_{M_2}

and a_{2,3} is the entry of A in the second row and third column, then

a_{2,3}=\begin{pmatrix}4&3\end{pmatrix}\begin{pmatrix}5\\4\end{pmatrix}=4\times5+3\times4=\boxed{32}

That is, the 2nd row, 3rd column entry of A is the product of the 2nd row of M_1 and the 3rd column of M_2.

6 0
1 year ago
I need to solve this equation: x= r-h/ y<br> for h and then for r
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X= r-h/y
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2 years ago
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