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Travka [436]
2 years ago
6

The product of any integer and zero

Mathematics
2 answers:
Andre45 [30]2 years ago
8 0
Anything times zero is simply zero, so the product of any integer and zero is always zero.
vlada-n [284]2 years ago
6 0
The product of any integer and zero is zero


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Need help RN!!!!
Vesnalui [34]

Answer:

log y = 3

Step-by-step explanation:

Substitute 10 for x, obtaining the following:

log y = 0.23(10) + 0.8, or

log y = 2.3 + 0.8, or 3.10, or (to the nearest whole number):

log y = 3

Step-by-step explanation:

Hope this helps:)

7 0
1 year ago
The perimeter of a rectangle is 13cm and its width is 11/4. find its length.
enyata [817]
Perimeter = 2 length + 2 width

P = 2(l) + 2(11/4)

13 = 2l +2* \frac{11}{4}

13 = 2l + \frac{2}{1} * \frac{11}{4}

13 = 2l + \frac{22}{4}     (subtract 22/4 from each side)

13 -\frac{22}{4} = 2l

13 -\frac{11}{2} = 2l

\frac{26}{2}  -\frac{11}{2} = 2l

\frac{15}{2}} = 2l

7.5 = 2l    (divide each side by 2)

7.5 ÷ 2 = l

3.75 = l

The answer is 3.75 or 3 \frac{3}{4}


6 0
2 years ago
A ring is now reduced to £840. This is a saving of 40% of the original price.
gladu [14]
The original price of the ring is <span>£</span>1400
6 0
2 years ago
Read 2 more answers
Absolute value of -12 and -15
kvasek [131]

Absolute value- the amount a number is away from zero. With this information, we can conclude,

|-12| = 12

|-15| = 15

5 0
1 year ago
Read 2 more answers
Complete the following proof. Given: Points R, S, T, Q on circle O Prove: m\overarc RS + m\overarc ST + m\overarc TQ + m\overarc
LekaFEV [45]

Answer:

360°

Step-by-step explanation:

From the figure attached,

R, S, T and Q are the points on a circle O.

Since, "measure of an arc of a circle is equal to the measure of the angle subtended by the arc at the center."

By this statement,

m(\widehat{RS})=m(\angle ROS)

m(\widehat{ST})=m(\angle SOT)

m(\widehat{TQ})=m(\angle TOQ)

m(major arc RQ) = m(∠QOR)

Now m(\widehat {RS})+m(\widehat{ST})+m(\widehat{TQ}) + m(major arc RQ) = m(\angle ROS)+m(\angle SOT)+m(\angle TOQ)+m(\angle QOR)

Since sum of all angles at a point = 360°

m(\widehat {RS})+m(\widehat{ST})+m(\widehat{TQ}) + m(major arc RQ) = 360°

4 0
1 year ago
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