Answer:
Step-by-step explanation:
Fraction of the total that is for corn (TC - Total corn):
fraction of the corn section that is for white corn (WC - white corn in the corn seccion):
we need to find the fraction of the whole field that is for the white corn.
For this we need to find how much is 
out of the 
destinated to corn, and this will be the fraction of the total that is for white corn. We find this fraction by multiplying the fraction of corn () by the fraction of white corn in the corn section ().
I will call the total fraction of white corn TWC, thus:
the answer is: of the whole field is planted with white corn
Answer:
Step-by-step explanation:
To find the HCF of 144 and 180
By using product of prime method
Firstly express 144 as a product of it prime and express 180 as a product of it prime
140=2×2×2×2×3×3
180=2×2×3×3×5
Common factor =2×2×3×3
36
in term of m
m=36
13m-3
To find m
Substitute for m when m=36
13(36)-3=
465
Answer:
11%
Step-by-step explanation:
1. Fill out the table with the correct numbers.
2. After you fillout the numbers, you should notice that under the column car and in the first row, there should be the number 18.
3. We know the total number of students under the age of 15 is 165.
4. To find the percent:
18/165 * 100
= 11%
Answer:
a)
We know that the total cost for the 150 shirts (plus a flat-rate of $25) is $1,825.
First, let's find how much costs each shirt.
First, the total cost of the shirts alone (neglecting the flat-rate) is:
$1,825 - $25 = $1,800
Then each shirt costs equal to the quotient of the cost and the number of shirts:
$1,800/150 = $12
Each shirt costs $12.
Then if you order T shirts, the total cost will be the flat-rate of $25 plus T times $12. The equation is:
C(T) = $25 + T*$12
b) C represents the cost
T represents the number of shirts ordered.
c) The initial value is the constant value, in this case, is $25
The rate of change is the coefficient that multiplies the independent variable (T), in the equation the rate of change is $12.
The question does not make sense.
The commutative property applies to addition and multiplication, not addition and subtraction.
The commutative property does not apply to subtraction or division because in those operations, the order of the numbers makes a difference, whereas in addition and subtraction the order does not make a difference.
For example:
Addition
5 + 4 = 9
4 + 5 = 9
5 + 4 = 4 + 5
Changing the order of the 4 and the 5 gives the same answer.
The commutative property does apply to addition.
Multiplication
5 * 4 = 20
4 * 5 = 20
5 * 4 = 4 * 5
Changing the order of the 4 and the 5 gives the same answer.
The commutative property does apply to multiplication.
Subtraction
5 - 4 = 1
4 - 5 = -1
5 - 4 is not equal to 4 - 5
Changing the order of the 4 and the 5 gives a different answer.
The commutative property does not apply to subtraction.
Division
5/4 = 1.25
4/5 = 0.8
1.25 is not equal to 0.8.
Changing the order of the 4 and the 5 gives a different answer.
The commutative property does not apply to division.
