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Debora [2.8K]
2 years ago
15

A caravan crossed 1,378 miles of desert in 85 days. it traveled 22 miles on the first day and 28 miles on the second day. if the

caravan traveled the same number of miles on each of the remaining days, how many miles did it travel on each of those day?
Mathematics
2 answers:
vlabodo [156]2 years ago
8 0
Um idk I forgot how to do this but ima ask my brother for you so he can tell you ok
Angelina_Jolie [31]2 years ago
8 0

Answer:

The caravan traveled 16 miles each day

Step-by-step explanation:

The caravan covers a distance of 1378 miles in 85 days. The first day he covered a distance of 22 miles and the second day it covered a distance of 28 miles. The remaining days will be 85 days minus the 2 days we already know the distance the caravan covered which is 83 days.

According to the question the remaining days he covered has equal distance for each day.

let y = miles covered each day in the remaining 83 days  

So total distance covered in those 83 days is 83 × y

Total distance covered for 85 days = 1378 miles

first day  = 22 miles

second day = 28 miles

Remaining 83 days = 83 × y

1378 = 22 + 28 + 83 × y

1378 - 22- 28 = 83y

1328 = 83y

y = 1328/83

y = 16

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denis-greek [22]

Answer:

d. The random variable is the number of years in which the temperature increased from the previous year.

Step-by-step explanation:

The random variable is the amount of years that have higher average temperatures than its previous year.

As the sample is from 5 years, the random variable can take values from 0 (where none of the years increase their average temperature from its previous year) to 4 (where every year increases the average temperature).

8 0
2 years ago
What is the midpoint of the segment shown below?<br> (-12,-3) (3,-8)
shepuryov [24]

Answer:

D

Step-by-step explanation:

In order to find the midpoint of a line segment on a graph, you must add both "x" coordinates, then divide by 2.

Then, add both "y" coordinates, and divide by 2.

5 0
1 year ago
AT&amp;T has a family plan of four lines for $125 and additional lines are $15 each per month. If Jason wants to spend at most $
denis-greek [22]

Given:

Cost of four lines = $125

Cost of each additional line = $15

Jason wants to spend at most $200 per month on cell phone expenses.

To find:

The inequality for the given situation.

Solution:

Let x be the number of additional line.

Cost of one additional line = $15

Cost of x additional line = \$15x

Total cost = Fixed cost + Addition cost

                = 125+15x

It is given that Jason wants to spend at most $200 per month on cell phone expenses. It means the total cost must be less than or equal to 200.

125+15x\leq 200

Therefore, the correct option is C.

8 0
1 year ago
If θ=0rad at t=0s, what is the blade's angular position at t=20s
babunello [35]
The attached figure represents the relation between ω (rpm) and t (seconds)
To find the blade's angular position in radians ⇒ ω will be converted from (rpm) to (rad/s)
              ω = 250 (rpm) = 250 * (2π/60) = (25/3)π    rad/s
              ω = 100 (rpm) = 100 * (2π/60) = (10/3)π    rad/s

and from the figure it is clear that the operation is at constant speed but with variable levels
            ⇒   ω = dθ/dt   ⇒   dθ = ω dt

            ∴    θ = ∫₀²⁰  ω dt  
 
while ω is not fixed from (t = 0) to (t =20)
the integral will divided to 3 integrals as follow;
       ω = 0                                          from t = 0  to t = 5
       ω = 250 (rpm) = (25/3)π            from t = 5   to t = 15
       ω = 100 (rpm) = (10/3)π            from t = 15 to t = 20

∴ θ = ∫₀⁵  (0) dt   + ∫₅¹⁵  (25/3)π dt + ∫₁₅²⁰  (10/3)π dt
     
the first integral = 0
the second integral = (25/3)π t = (25/3)π (15-5) = (250/3)π
the third integral = (10/3)π t = (25/3)π (20-15) = (50/3)π

∴ θ = 0 + (250/3)π + (50/3)π = 100 π

while the complete revolution = 2π
so instantaneously at t = 20
∴ θ = 100 π - 50 * 2 π = 0 rad

Which mean:
the blade will be at zero position making no of revolution = (100π)/(2π) = 50
















3 0
2 years ago
The function D(t) defines a traveler's distance from home, in miles, as a function of time, in hours. D(t) = StartLayout enlarge
nalin [4]

- At 2 hours, the traveler is 725 miles from home.

- At 3 hours, the distance is constant, at 880 miles. --> TRUE.

- The total distance from home after 6 hours is 1,062.5 miles --> TRUE.

Step-by-step explanation:

The function D(t) is defined as follows:

D(t) = 300t+125 for t< 2.5

D(t) = 880 for 2.5 \leq 3.5

D(t) = 75t+612.5 for t\leq 6

Where

t is the time in hours

D(t) is the distance covered, in miles, after t hours

Now let's analyze the different statements:

- The starting distance, at 0 hours, is 300 miles. --> FALSE. In fact, if we substitute t = 0 into the 1st equation, we get

D(0) = (300)(0)+125 = 125

So, the distance at t = 0 is 125 miles.

- At 2 hours, the traveler is 725 miles from home. --> TRUE. In fact, if we substitute t = 2 into the 1st equation,

D(2) = (300)(2)+125 = 725

- At 2.5 hours, the traveler is 875 miles from home. --> FALSE. In fact, for t=2.5 we have to use the 2nd equation, which states that the distance is:

D(t) = 880

So, not 875 miles.

- At 3 hours, the distance is constant, at 880 miles. --> TRUE. This is clearly visible from the 2nd equation: for t between 2.5 and 3.5 (so, in this case), the distance is

D(t) = 880

- The total distance from home after 6 hours is 1,062.5 miles --> TRUE. In fact, if we replace t = 6 into the last equation,

D(6)) = 75(6)+612.5=1062.5

Learn more about functions:

brainly.com/question/3511750

brainly.com/question/8243712

brainly.com/question/8307968

Learn more about  distance:

brainly.com/question/3969582

#LearnwithBrainly

4 0
1 year ago
Read 2 more answers
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