Question

Find the product. (3a^4 + 4)^2

Answer 1

9a8+24a4+16

Make sure that 8 and 4 are to the power

Answer 2

Answer: The product is $9a^8+24a^4+16$

Step-by-step explanation:

Since we have given that

$(3a^4+4)^2$

As we know that

$(a+b)^2=a^2+2ab+b^2$

So, it becomes,

$(3a^4 + 4)^2=(3a^4)^2+2\times 3a^4\times 4+(4)^2\\\\=9a^8+24a^4+16$

Hence, the product is $9a^8+24a^4+16$