answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Maslowich
2 years ago
11

Ten major recording acts are able to play at the stadium. If the average profit margin for a concert is $175,000, how much would

the stadium clear for all of these events combined?
Mathematics
2 answers:
nikitadnepr [17]2 years ago
7 0

Answer: Total amount the stadium would clear for all of these events combined is $1750000

Step-by-step explanation:

Since we have given that

Number of major recording acts are able to play at the stadium = 10

Average profit margin for a concert = $175000

We need to find the amount that the stadium clear for all of these events combined

As we know the formula for "Average"

Average=\frac{\text{ Total sum}}{\text{ Number of recording acts }}\\\\175000=\frac{\text{total sum}}{10}\\\\175000\times 10=Total\ sum\\\\\$1750000=Total\ sum

Hence, total amount the stadium would clear for all of these events combined is $1750000.

marshall27 [118]2 years ago
6 0

Answer:

$1,750,000

Step-by-step explanation:

Average profit from all ten events = $175,000

Total number of events = 10

Total profit from all ten events =

(Average profit from all ten events) x ( Total number of events)

$175,000 x 10\\= 1, 750,000\\

The answer = $1,750,000

You might be interested in
A population has a standard deviation of 80. A random sample of 400 items from this population is selected. The sample mean is d
Helga [31]

Answer:

ME= 1.8808 * \frac{80}{\sqrt{400}} =7.5232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma =80 represent the population standard deviation

n=400 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

Since the Confidence is 0.94 or 94%, the value of \alpha=0.06 and \alpha/2 =0.03, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that z_{\alpha/2}=1.8808

The margin of error is given by:

ME= 1.8808 * \frac{80}{\sqrt{400}} =7.5232

4 0
2 years ago
Brenda is rolling a six-sided die and flipping a coin. Complete each of the following sentences regarding the probabilities invo
sveta [45]
So for number there are 6 possible outcomes nad 5 is one of them so 1/6
He next one there are 2 outcomes and heads is 1 outcome so 1/2
For the next one you have to multiply them together so you get 1/12
And the events are independent because whatever you roll on the die won’t affect the coin(it actually does on a very small scale but I don’t think you go into that much detail for high school maths)
8 0
2 years ago
Find the distance from (4, −7, 6) to each of the following.
LenKa [72]

Answer:

(a) 6 units

(b) 4 units

(c) 7 units

(d) 9.22 units

(e) 7.21 units

(f) 8.06 units

Step-by-step explanation:

The distance d from one point (x₁, y₁, z₁) to another point (x₂, y₂, z₂) is given by;

d = √[(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²]

Now from the question;

<em>(a) The distance from (4, -7, 6) to the xy-plane</em>

The xy-plane is the point where z is 0. i.e

xy-plane = (4, -7, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, -7, 0)</em>

d = √[(4 - 4)² + (-7 - (-7))² + (0 - 6)²]

d = √[(0)² + (0)² + (-6)²]

d = √(-6)²

d = √36

d = 6

Hence, the distance to the xy plane is 6 units

<em>(b) The distance from (4, -7, 6) to the yz-plane</em>

The yz-plane is the point where x is 0. i.e

yz-plane = (0, -7, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, -7, 6)</em>

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 6)²]

d = √[(4)² + (0)² + (0)²]

d = √(4)²

d = √16

d = 4

Hence, the distance to the yz plane is 4 units

<em>(c) The distance from (4, -7, 6) to the xz-plane</em>

The xz-plane is the point where y is 0. i.e

xz-plane = (4, 0, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, 0, 6)</em>

d = √[(4 - 4)² + (-7 - 0)² + (6 - 6)²]

d = √[(0)² + (-7)² + (0)²]

d = √[(-7)²]

d = √49

d = 7

Hence, the distance to the xz plane is 7 units

<em>(d) The distance from (4, -7, 6) to the x axis</em>

The x axis is the point where y and z are 0. i.e

x-axis = (4, 0, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, 0, 0)</em>

d = √[(4 - 4)² + (-7 - 0)² + (6 - 0)²]

d = √[(0)² + (-7)² + (6)²]

d = √[(-7)² + (6)²]

d = √[(49 + 36)]

d = √(85)

d = 9.22

Hence, the distance to the x axis is 9.22 units

<em>(e) The distance from (4, -7, 6) to the y axis</em>

The x axis is the point where x and z are 0. i.e

y-axis = (0, -7, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, -7, 0)</em>

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 0)²]

d = √[(4)² + (0)² + (6)²]

d = √[(4)² + (6)²]

d = √[(16 + 36)]

d = √(52)

d = 7.22

Hence, the distance to the y axis is 7.21 units

<em>(f) The distance from (4, -7, 6) to the z axis</em>

The z axis is the point where x and y are 0. i.e

z-axis = (0, 0, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, 0 6)</em>

d = √[(4 - 0)² + (-7 - (0))² + (6 - 6)²]

d = √[(4)² + (-7)² + (0)²]

d = √[(4)² + (-7)²]

d = √[(16 + 49)]

d = √(65)

d = 8.06

Hence, the distance to the z axis is 8.06 units

5 0
2 years ago
Santiago hopes to buy a 4 horse trailer for about $12000. Describe all the numbers that when rounded to the nearest hundred are
jok3333 [9.3K]
To round a number to the nearest hundred, we count two places to the left of the decimal point, or from the last digit if the number is a whole number.

If the second digit from the last digit is upto 5, we add 1 to the preceding digit and we complete the last two numbers with zeros.

Therefore, any number from 11,950 to 12,049, will result to 12,000 when rounded to the nearest hundred.
8 0
2 years ago
Read 2 more answers
Use properties to rewrite the given equation. Which equations have the same solution as 2.3p – 10.1 = 6.5p – 4 – 0.01p? Select t
tankabanditka [31]

Help me I’m on the test review and I don’t get it someone help stupid edgenuity teachers are too lazy to teach us themselves

4 0
2 years ago
Read 2 more answers
Other questions:
  • Which expression is equivalent to 4/9(2n-3)
    8·1 answer
  • a 12 foot tall building casts on 8 foot long long shadow. how long of a shadow will a 5 foot tall women have
    15·1 answer
  • Charlie wants to order lunch for his friends. He'll order 5 sandwiches and a $3 kid's meal for his little brother. Charlie has $
    15·2 answers
  • Kendra charges $11 to shovel a driveway. She shoveled 4 driveways on Saturday and then some more on Sunday. She made $143 for th
    8·2 answers
  • According to the table listing average daily expenses for a tourist by country based on high and medium categories, Brazil has a
    9·2 answers
  • For the quadrant in which the following point is located, determine which of the functions are positive. (-4, 3) sin cos tan sec
    7·1 answer
  • An Article in the Journal of Sports Science (1987, Vol. 5, pp. 261-271) presents the results of an investigation of the hemoglob
    13·1 answer
  • 5 Adoncia makes a scale drawing of the front of
    15·1 answer
  • An orchestra of 25 members bought tickets, at all different prices, to a concert, and the mean price paid was $82. A new musicia
    14·1 answer
  • A jar of 150 jelly beans contains 22 red jelly beans, 38 yellow, 20 green, 28 purple, 26 blue, and the rest are orange.Let B = t
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!