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2 years ago

All of these are common spring arrangements on SLA systems except A. Torsion Bar

Computers and Technology

2 answers:

iren2701 [21]2 years ago

3 0

The answer is letter (B)

LiRa [457]2 years ago

3 0

Answer: The correct answer is Choice B - Mounted on the Shock.

Explanation: Torsion bar, between the control arms and on the upper control arm are all common spring arrangements on the SLA systems. Mounted on the shock is not, which makes choice B the correct answer.

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Answer:

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1 year ago

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2 years ago

Find a 95% confidence interval for the mean failure pressure for this type of roof panel.The article "Wind-Uplift Capacity of Re

aliya0001 [1]

Answer:

The 95% confidence interval would be given by (2.351;3.525)

Explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=2.938$

The sample deviation calculated $s=0.472$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that $t_{\alpha/2}=2.78$

Now we have everything in order to replace into formula (1):

$2.938-2.78\frac{0.472}{\sqrt{5}}=2.351$

$2.938+2.78\frac{0.472}{\sqrt{5}}=3.525$

So on this case the 95% confidence interval would be given by (2.351;3.525)

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2 years ago

Exercise 3.6.9: 24 vs. "24"5 points

Anton [14]

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2 years ago

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2 years ago