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2 years ago

One class of pollutants that can cause excessive growth of algae is

1 answer:

3 0

Hi one class of pollutants that can cause excessive growth of algae is-- inorganic plant nutrients.
Hope this helps you.

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The wells that contain the DNA samples are placed next to the negatively charged electrode in the electrophoresis box (chamber)

Katen [24]

Answer:

DNA is negatively charged

Explanation:

Electrophoresis: In biology, the term "electrophoresis" is described as one of the different laboratory technique that is being utilized to separate protein molecules, DNA, and RNA one the basis of their electrical charge and size. Therefore, a specific amount of "electric current" is being used to move different molecules that are required to be separated through a "gel". The given gel contains pores that generally works like a "sieve" and thus allows every small molecule to proceed faster as compared to the larger molecules.

DNA stands for "deoxyribonucleic acid" is determined as a long molecule that ought to contain an individual's unique "genetic code" and generally carried information associated for making proteins in an individual's body.

In the question above, the correct answer is "DNA is negatively charged".

3 0

2 years ago

Your science class has taken swabs throughout the school. The image shows the petri dish containing a bacterial culture that dev

tresset_1 [31]

Answer:

answer is D

Explanation:

because that is the correct one

3 0

2 years ago

Read 2 more answers

Directed pressure causes _____.

prisoha [69]

C. Sedimentary Layers, sedimentary rocks are created as a result of high pressure :)

I hope this helped!

5 0

2 years ago

Read 2 more answers

Two autosomal genes, J and K, are 60 map units apart. You perform the following testcross: J K / j k x j k / j k. At what freque

Dmitry [639]

Answer:

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%

Explanation:

To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.

The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.

So, en the exposed example:

J and K are autosomal genes

J and K are separated by 60 M.U.

60 M.U. means that there is 60% of recombination.

Cross) J K / j k x j k / j k

Gametes) JK Parental jk, jk, jk, jk

jk Parental

Jk Recombinant

jK Recombinant

One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.

1 M.U. -------------- 1% recombination

60 M.U. ------------ 60% recombination

30% Jk + 30% jK

100 M.U. - 60 M.U. = 40 M.U.

40M.U.--------------40 % Parental (Not recombinant)

20% JK + 20% jk

Punnet Square) JK jk Jk jK

jk JK/jk jk/jk Jk/jk jK/jk

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%

3 0

2 years ago

In certain bacteria, an oval shape (O) is dominant over round (o) and thick cell walls (T) are dominant over thin (t). Draw on a

seropon [69]

Answer:

Consider the heterozygous oval, thick cell walled bacteria to have the alleles OoTT and the thin cell walled bacteria to have alleles oott. Results will be 50% oval, thick walled bacteria and 50% round, thick walled bacteria. This will be the F1 progeny.

When the oval, thick walled bacteria from the F1 progeny is cross bred with round, thick walled bacteria then 25 percent of the bacteria will be heterozygous oval, thick walled. 25 percent will be heterozygous oval and heterozygous thick walled. 25 percent will be round and thick walled. 25 percent will be round and thin walled.

6 0

2 years ago