Number of dinners = 125 Individual portion = 8 oz. Size of can = 32 oz.

The volume of a cylinder is 2,200Pi cubic inches. The diameter of the circular base is 10 inches. What is the height of the cyli

svet-max [94.6K]

I think it’s 220 inches

6 0

2 years ago

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Solve the system of linear equations using multiplication.

Anna71 [15]

Answer:

$(8,-1)$

Step-by-step explanation:

The given system is:

$3x+3y=21$

$6x+12y=36$

Since I prefer to use smaller numbers I'm going to divide both sides of the first equation by 3 and both sides of the equation equation by 6.

This gives me the system:

$x+y=7$

$x+2y=6$

We could solve the first equation for $x$ and replace the second $x$ with that.

Let's do that.

$x+y=7$

Subtract $y$ on both sides:

$x=7-y$

So we are replacing the second $x$ in the second equation with $(7-y)$ which gives us:

$(7-y)+2y=6$

$7-y+2y=6$

$7+y=6$

$y=6-7$

$y=-1$

Now recall the first equation we arranged so that $x$ was the subject. I'm referring to $x=7-y$ .

We can now find $x$ given that $y=-1$ using the equation $x=7-y$ .

Let's do that.

$x=7-y$ with $y=-1$ :

$x=7-(-1)$

$x=7+1$

$x=8$

So the solution is (8,-1).

We can check this point by plugging it into both equations.

If both equations render true for that point, then we have verify the solution.

Let's try it.

$3x+3y=21$ with $(x,y)=(8,-1)$ :

$3(8)+3(-1)=21$

$24+(-3)=21$

$21=21$ is a true equation so the "solution" looks promising still.

$6x+12y=36$ with $(x,y)=(8,-1)$ :

$6(8)+12(-1)=36$

$48+(-12)=36$

$36=36$ is also true so the solution has been verified since both equations render true for that point.

5 0

1 year ago

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Tommy has a piece of toast that has butter on one side, and he dropped it twice. Both times, it landed with the butter side up.

Shkiper50 [21]

Since probability is the measure of the likelihood that an event will occur.so, maybe 5.

5 0

2 years ago

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Which statements about the local maximums and minimums for the given function are true? Choose three options.

Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

8 0

2 years ago

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Anton will be constructing a segment bisector with a compass and straightedge, while Maxim will be constructing an angle bisecto

Genrish500 [490]

The similarities are;

Compass and a straight edge required for both construction

Both construction includes a line drawn from the intersection of arcs to bisect a segment or an angle

The bases for the construction of both bisector are the ends of segment and the angle to be bisected

The width of the compass when drawing intersecting arcs, is more than half the width of the segment or angle being bisected

The differences are;

Two points of intersection of arcs are used in the segment bisector while only one is requited in an angle bisector
The bisecting line crosses the segment in a segment bisector, while it stops at the vertex of the angle being bisected in an angle bisector

The sources of the above equations are as follows;

The steps to construct a segment bisector are;

Place the needle of the compass at one of the ends of the line segment to be bisected

Widen the compass so as to extend more than half of the length of the segment to be bisected

Draw two arcs, one above, and the other below the line

Place the compass needle at the other end and with the same compass width draw arcs that intersects with the arcs drawn in the above step

Draw a line segment by placing the ruler on the points of intersection of the arcs above and below the line

The steps to construct an angle bisector are;

With the compass needle at the vertex, open the pencil end such that arcs can be drawn on the rays (lines) forming the angle

Draw an arc on both lines forming the angle

Place the compass needle at one of the intersection points and draw an arc in between the lines forming the angle

Repeat the above step with the same compass width from the other intersection point with the rays forming the angle

Join the point of intersection of the two arcs to the vertex of the angle to bisect the angle

Therefore, we have;

The similarities are;

A compass and a straight edge can be used for both construction

A straight line is drawn from the point of intersection of arcs to bisect the segment or the angle

The arcs are drawn from the ends of the segment or angle to be bisected

The width of the compass is more than half the width of the line or angle when drawing the arcs

The differences are;

In a segment bisector, the intersection point is above and below the line, while in an angle bisector only one pair of arcs are drawn to intersect above the line

The bisecting line passes through the segment being bisected, while the line stops at the vertex in an angle bisector

Learn more about the construction of segment and angle bisectors here;

brainly.com/question/17335869

brainly.com/question/12028523

7 0

1 year ago