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KatRina [158]
2 years ago
13

A deli sells ham for $2.98 per half pound. Kyle incorrectly says that the unit rate is $1.49 per pound. Explain Kyle's mistake a

nd determine the correct price per pound. Show your work.
Mathematics
2 answers:
sveticcg [70]2 years ago
7 0
The correct answer per pound is $1.49 per pound. Kyle is correct because dividing 2.98/2= 1.49 or multiplying Kyle's answer by 2 will give you the correct amount!
Mekhanik [1.2K]2 years ago
7 0

Answer:

$5.96

Kyle mistake was that he misinterpreted the question by taking the price for half pound to be the full pound price , and he also thought he was required to calculate half the price  . ($2.98/2) = $1.49

Step-by-step explanation:

Price per half pound = $2.98

Incorrect price used by Kyle = $1.49 / round

Correct price per pound = $2.98 *2 =$5.96

Kyle mistake was that he misinterpreted the question by taking the price for half pound to be the full pound price , and he also thought he was required to calculate half the price  . ($2.98/2) = $1.49

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A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s
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Answer:

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

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