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2 years ago

Consider the equation y = 4.2x and the table below that represents this relationship.

Mathematics

2 answers:

Vadim26 [7]2 years ago

3 0

Answer:

$k=4.2$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In this problem we have

$y=4.2x$

The constant of proportionality K is the same that the slope of the linear equation

The value of k is

$k=4.2$

abruzzese [7]2 years ago

3 0

Answer:

The answer is 4.2

Step-by-step explanation:

i did it on edge

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AURORKA [14]

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷Yes.

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DOGE

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2 years ago

The sum of the four angles in a rectangle is always 180 degrees true or false?

dem82 [27]

A rectangle has 4 sides
each side is a right angle
a right angle by definition is 90 degrees
$90 + 90 + 90 + 90 = 360\\ or\\ 90 * 4 = 360$
False

7 0

2 years ago

Read 2 more answers

Cora is playing a game that involves flipping three coins at once. Let the random variable HHH be the number of coins that land

arlik [135]

Answer:

0.875

Step-by-step explanation:

P(H=0) = 0.125

P(H=1) = 0.375

P(H=2) = 0.375

P(H=3) = 0.125

P(H<3) = P(H=0) + P(H=1) + P(H=2)

P(H<3) = 0.125 + 0.375 + 0.375

P(H<3) = 0.875

4 0

2 years ago

Read 2 more answers

In parallelogram ABCD , diagonals AC⎯⎯⎯⎯⎯ and BD⎯⎯⎯⎯⎯ intersect at point E, AE=x2−16 , and CE=6x .

MAXImum [283]

Answer:

<h3>AC=96 units.</h3>

Step-by-step explanation:

We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.

$AE=x^2-16.$ , and CE=6x .

<em>Note: The diagonals of a parallelogram intersects at mid-point.</em>

Therefore, AE = EC.

Plugging expressions for AE and EC, we get

$x^2-16=6x.$

Subtracting 6x from both sides, we get

$x^2-16-6x=6x-6x$

$x^2-6x-16=0$

Factoriong quadratic by product sum rule.

We need to find the factors of -16 that add upto -6.

-16 has factors -8 and +2 that add upto -6.

Therefore, factor of $x^2-6x-16=0$ quadratic is (x-8)(x+2)=0

Setting each factor equal to 0 and solve for x.

x-8=0 => x=8

x+2=0 => x=-2.

We can't take x=-2 as it's a negative number.

Therefore, plugging x=8 in EC =6x, we get

EC = 6(8) = 48.

<h3>AC = AE + EC = 48+48 =96 units.</h3>

5 0

2 years ago

At a college, 72% of courses have final exams and 46% of courses require research papers. Suppose that 31% of courses have a res

beks73 [17]

Answer:

0.25

Step-by-step explanation:

72% of courses have final exams and 46% of courses require research papers which means probability of 0.72 for courses that have final exams and 0.46 for courses that require research papers.

31% of courses have a research paper and a final exam, which means probability of 0.31 for both courses with exams and research papers, using Venn diagram approach, find picture attached to the solution.

P(R or E) = P(R) + P(E) - P(R and E), which gives:

P(R or E) = 0.15 + 0.41 - 0.31

P(R or E) = 0.25.

6 0

2 years ago