The length of a rectangle is represented by x2 + 3x + 2, and the width is represented by 4x.

A ball is thrown from an initial height of 2 meters with an initial upward velocity of 15/ms . The ball's height h (in meters) a

Irina-Kira [14]

The height that a ball reaches at a certain time t is given by the equation,
h = 2 - 15t + 5t²
We are asked to compute for the values of t that would allow the ball to reach a height of 7 meters.

Substitute the 7 to the equation,
7 = 2 - 15t + 5t²
Transposing,
5t² - 15t - 7 + 2 = 0
Simplifying,
5t² - 15t - 5 = 0
Divide the equation by 5,
t² - 3t - 1 = 0

The values of t can be calculated through the quadratic formula,
t = (-b +/- sqrt(b² - 4ac))/2a

Substituting,
t = (3 +/-sqrt (9 - 4(-1)) / 2(1)
t = 3.3 or t = -0.30

Since, we cannot have t as a negative number hence, our final answer is:
<em> t = 3.3 s</em>

4 0

2 years ago

Paul's mom, Gina, owns her home outright, without a mortgage. It is currently worth $100,000. If she could get five percent inte

Gala2k [10]

Use the formula i = p*r*t.

Here, p = $100000, r = 0.05 and t = 1 (year)

The interest would be i = $100000*0.05*1 = $5000 per year.

7 0

2 years ago

Read 2 more answers

On average, water flows over a particular water fall at a rate of 2.05 x 105 cubic feet per second. One cubic foot of water weig

iren [92.7K]

Answer:

5.024 × 10^8 tons /day

Step-by-step explanation:

This question has to deal with conversion

We are told in the question that:

On average, water flows over a particular water fall at a rate of 2.05 x 10^5 cubic feet per second.

Water flow rate = 2.05 × 10^5 ft³/s

From the question,

One cubic foot of water weighs 62.4 lb.

1 ft³ = 62.4 lb

1 ton = 2200 lb

We are to calculate the flow rate in tons per day

Hence,

1 ft³ = 62.4 lb

2.05 × 10^5 ft³ =

Cross Multiply

2.05 × 10^5 × 62.4

= 12792000lb

Hence the water flow rate = 12792000lb/s

From the question,

2200 lb = 1 ton

12792000 Ib =

Cross Multiply

12792000lb × 1 ton/2200 lb

= 5814.5454545 tons

Hence the water flow rate = 5814.5454545 tons/second

We want the flow rate to be in tons/day

1 ton / second = 86400 tons / day

5814.5454545 tons/second = x tons/ day

Cross Multiply

x = 5814.5454545 tons/second × 86400 tons /day/ 1 ton / second

= 502376727.27 tons/day

= 5.0237672727 × 10^8 tons/day

Approximately ≈ 5.024 × 10^8 tons /day

Therefore, the rate of water flow in tons of water per day is 5.024 × 10^8 tons of water /day

7 0

2 years ago

The graph of f(x) = x2 is translated to form g(x) = (x – 5)2 + 1. On a coordinate plane, a parabola, labeled f of x, opens up. I

Lostsunrise [7]

Answer:

The option which is:

On a coordinate plane, a parabola opens up. It goes through (2, 10), has a vertex at (5, 1), and goes through (8, 10).

Step-by-step explanation:

At first we should know the rules of translation

1) {f(x) + a} is f(x) shifted up (a) units

2) {f(x) – a} is f(x) shifted down (a) units

3) {f(x + a)} is f(x) shifted left (a) units.

4) {f(x – a)} is f(x) shifted right (a) units.

Given:

f(x) = x²

g(x) = (x-5)² + 1

By comparing [ the translation from f(x) to g(x) ] with the rules of translation

We can deduce that g(x) is the image of f(x) by translation 5 units right and 1 unit up ( rules 1 and 4)

See the attached figure which represent the graph of f(x) and g(x)

As shown g(x) goes through (2, 10), has a vertex at (5, 1), and goes through (8, 10)

3 0

2 years ago

Read 2 more answers

A company receives shipments of a component used in the manufacture of a component for a high-end acoustic speaker system. When

Tanya [424]

Answer:

$ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434$

Step-by-step explanation:

For this case we have a sample size of n = 250 units and in this sample they found that 24 units failed one or more of the tests.

We are interested in the proportion of units that fail to meet the company's specifications, and we can estimate this with:

$\hat p = \frac{24}{250}= 0.096$

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 98% confidence interval the value of $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.33$

And the margin of error would be:

$ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434$

4 0

2 years ago