Answer:
There is no specific linear equation for this scenario because there is only one possible length for the pole.
Step-by-step explanation:
0.25 inches represents 1 mile
----------------------------------------------
Find 1 inch:
----------------------------------------------
1 inch represents 1 ÷ 0.25 miles
1 inch represents 4 miles
----------------------------------------------
Find 3.75 inches:
----------------------------------------------
1 inch represents 4 miles
3.75 inches represent 4 x 3.75 miles
3.75 inches represent 15 miles
----------------------------------------------
Find 2.25 inches:
----------------------------------------------
1 inch represents 4 miles
2.25 inches represent 4 x 2.25 miles
2.25 inches represent 9 miles
----------------------------------------------
Find Area:
----------------------------------------------
Area = Length x Width
Area = 15 x 9
Area = 135 miles²
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Answer: 135 miles²
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Step-by-step explanation:
Let
x
be the kg of coffee of brand A in the mix and
y
be the kg of coffee of brand B in the mix.
The total kg must be
50
.
x
+
y
=
50
The cost per kg of the mix must br
$
7.20
. For this, the total cost of the mix will be
6
x
+
8
y
, so the total cost per kg of the mix will be
6
x
+
8
y
50
.
6
x
+
8
y
50
=
7.20
Now that we have our two equations, we can solve.
6
x
+
8
y
=
7.20
⋅
50
6
x
+
8
y
=
360
From the first equation, we can multiply both sides by
6
to get:
6
x
+
6
y
=
300
Subtracting, we get:
2
y
=
60
y
=
30
Thus, we need
30
kg of brand B in our mix. This means that
50
−
30
=
20
kg will be of brand A.
Answer:
The domain of f(x) is x>-2, so the range of f-1(x) is y>-2
The range of f(x) is y>-1, so the domain of the f-1(x) is x>-1
Step-by-step explanation:
Answer:
the probability that the exceeded 65 = 0.3707
The average score of the 36 golfers exceeded 65
= 36 X 0.3707 = 13.3452
Step-by-step explanation:
<u>Step 1</u>:-
The average score of all golfers for a particular course has a mean of 64 and a standard deviation of 3.
mean (μ) = 64
standard deviation (σ) =3
by using normal distribution
given (μ) = 64 and (σ) =3
i) when x =65
P( X≥ 65) = P(z≥0.33)
= 0.5 - A(z₁)
= 0.5 - 0.1293 (see normal table)
= 0.3707
The average score of the 36 golfers exceeded 65
= 36 X 0.3707 = 13.3452
