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liq [111]
2 years ago
5

Julie wants to make 800g of a 15% alcohol solution by mixing 20% solution and a 4% solution. How many grams of each kind does sh

e need?
If a 20% and a 4% alcohol solution weigh x g and y g respectively

solve with equation please and show steps thank you ;)
Mathematics
1 answer:
Kipish [7]2 years ago
3 0
X+y=800; 0.20x+0.04y=0.15×800=120.
y=800-x so 0.20x+0.04(800-x)=120.
0.20x+32-0.04x=120.
0.16x=88 and x=88/0.16=550g making y=250g.
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Answer: 16.2%

Step-by-step explanation:

You can find the cost of equity using the Capital Asset Pricing Model (CAPM).

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2 years ago
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
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Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

Z_{1-\alpha /2}= Z_{0.95}= 1.645

[10.41±1.645*(\frac{3.71}{\sqrt{28} } )]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0
2 years ago
The east room of the White House is 79 feet long by 36 feet wide what is the area and what is the perimeter of the east room
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4 0
2 years ago
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5 0
2 years ago
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Courtney has a total of 88 stamps worth $15.56. Some are 25 cent stamps and some 2 cent stamps. How many of each does she have
Oksi-84 [34.3K]
<span>88 stamps -------------------- >  $15.56
A------------------------------>number of  </span>stamps ------------ ><span>25 cent
B----------------------------- > </span>number of  stamps ------------ >2 cent

A+B=88------------------ > A=88-B
0.25A+.02B=15.56
resolving
0.25(88-B)+0.02B=15.56
22-0.25B+0.02B=15.56
-0.23B=-6.44----------------------- > B=28 stamps of 2 cent
A=88-B-- >88-28=60------------- > A=60 stamps of 25 cent
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2 years ago
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