Answer:
The 5' end has free phosphate group while the 3' end has free OH group.
Explanation:
Each DNA strand has two ends that differ from each other with respect to the functional group. The nucleotide present at the 5' end of a DNA strand has a free phosphate group. This phosphate group of other nucleotides of the DNA strand is bonded in phosphodiester bonds. Likewise, the 3' end of a DNA has a free OH group. This makes the two ends of a DNA strand quite different from each other. A DNA new nucleotide can be added to the 3' end due to the presence of a free OH group.
Use the Hardy Weinburg
equation of allelic frequency.
P2+2pq+q2=1
174/1378 = 0.126 = q2
Therefore q2 = 0.126; q = 0.355
If q = 0.355 and we understand that p + q = 1, then
P = 1 – 0.355 = 0.645
To find homozygous dominant population (p2);
(0.645)2 x 1378 = 0.416 x 1378 = 573
Heterozygous popualiton (2pq);
(2 x 0.645 x 0.355) x 1378 = 0.458 x 1378= 631
Recessive indviduals (q2) = 174
The process that is detailed here, is knows as the Adrenaline Process, Or (Adrenaline). Adrenaline gives the body an extra boost of energy when in a hurry, in shock, or scared.
Answer:
C
Explanation:
A)
DNA directs the synthesis of RNA.
B)
DNA splits into two strands of RNA.
C)
A strand of DNA is used as a template for the formation of RNA.
D)
Two strands of RNA are formed by copying each of the strands of DNA.
The correct answer would be that <u>a strand of DNA is used as a template for the formation of RNA.</u>
<em>Transcription is a process during which RNA is synthesized using DNA as a template. The coding strand of the DNA is utilized as a template for the formation of messenger RNA. During this process, the double helix structure of the DNA is unwound by an enzyme and the coding strand is bound by a short DNA strand at the beginning of a gene while another enzyme adds RNA nucleotide bases to elongate the short strand.</em>
The correct option is C.