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2 years ago

What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

2 answers:

6 0

The problem is: What is the value of the expression

$\displaystyle{ i^0\cdot i^1\cdot i^2\cdot i^3\cdot i^4$ .

We know that $i^0=1$ and $i^2=-1$ . Thus:

$i^0=1\\\\i^1=i\\\\i^2=-1\\\\i^3=i^2\cdot i=-1 \cdot i=-i\\\\i^4=(i^2)^2=(-1)^2=1.$

So,

$i^0\cdot i^1\cdot i^2\cdot i^3\cdot i^4=1 \cdot i \cdot (-1) \cdot (-i) \cdot 1= i \cdot (-1) \cdot (-i)= i \cdot i=-1.$

Answer: B) -1.

Tom [10]2 years ago

5 0

The answer is B. -1 on Edg ;))

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Answer:

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Step-by-step explanation:

y=2x^2-8x+10

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2 years ago

LMN is a straight angle. Find m LMP and m NMP

viva [34]

Answer:

(-16x + 13)° + (-20x + 23)° = 180° ( St. angle)

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2 years ago

The area of the rectangle is 64.8 square centimeters. What is the perimeter of the rectangle? One group of ten tenths and one gr

9966 [12]

Answer:

(a) $Perimeter = 32.2\ cm$

(b) 100

Step-by-step explanation:

Solving (a):

Given

Shape: Rectangle

$Area = 64.8$

Required

Calculate the perimeter.

Area is calculated as:

$Area = L * W$

Where

$L = Length$ and $W = Width$

Substitute 64.8 for Area

$64.8 = L * W$

Make L the subject:

$L = \frac{64.8}{W}$

Perimeter is calculated as:

$P = 2 * (L + W)$

Substitute 64.8/W for L

$P = 2 * (\frac{64.8}{W} + W)$

$P = \frac{129.6}{W} + 2W$

To solve further, we take the derivative of P and set it to 0, afterwards.

$dP = -\frac{129.6}{W^2} + 2$

Set to 0

$0 = -\frac{129.6}{W^2} + 2$

Collect Like Terms

$\frac{129.6}{W^2} = 2$

Cross Multiply:

$2W^2= 129.6$

Divide through by 2

$W^2 = 64.8$

Take square roots

$W = \sqrt{64.8$

$W = 8.05$

Recall that:

$L = \frac{64.8}{W}$

So:

$L= \frac{64.8}{8.05}\\$

$L= 8.05$

The perimeter is:

$Perimeter = 2 * (8.05 + 8.05)$

$Perimeter = 2 * (16.10)$

$Perimeter = 32.2\ cm$

Solving (b):

Given

((1 Group of 10 tenths) and (1 group of 8 tenths))/(6 groups of 3 tenths)

Required

Solve

$Tenths = \frac{1}{10}$

So, the expression becomes:

((1 Group of $10 * \frac{1}{10}$ ) and (1 group of $8 * \frac{1}{10}$ ))/(6 groups of $3 * \frac{1}{10}$ )

This gives:

((1 Group of $\frac{10}{10}$ ) and (1 group of $\frac{8}{10}$ ))/(6 groups of $\frac{3}{10}$ )

Group means product, so the expression becomes:

$\frac{(1 * \frac{10}{10} \ and\ 1 * \frac{8}{10})}{6 * \frac{3}{10}}$

And, as used here means addition

$\frac{(1 * \frac{10}{10} + 1 * \frac{8}{10})}{6 * \frac{3}{10}}$

Simplify:

$\frac{(1 * 1 + 1 * 0.80)}{6 *0.30}$

$\frac{(1 + 0.80)}{1.80}$

$\frac{1.80}{1.80}$

$= 1.00$

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2 years ago

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Answer:

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Step-by-step explanation:

Let's see.

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