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lesantik [10]
2 years ago
12

Lupe can ride her bike at a rate of 20 mph when there is no wind. On one particular day, she rode 2 miles against the wind and n

oticed that it took her the same amount of time as it did to ride 3 miles with the wind. How fast was the wind blowing that day? 4 mph 7 mph 10 mph 12 mph
Mathematics
2 answers:
jekas [21]2 years ago
8 0
Hello there! Your answer should be 4 mph. Reasoning:
2 = (20 - x) * t 
<span>3 = (20 + x ) * t </span>
Time is the same for both equations. Solve for T.
2/(20-x) = 3/(20+x)
<span>the answer is 4 mph.
Please tell me if I was right!</span>
lana [24]2 years ago
4 0
Let wind speed = x mph 

when she rode 2 miles against the wind we have:-
speed = distance / time so
20 - x  = 2 / t -------(1)      where t is the time she took.

when riding with the wind we have 

20 + x = 3 / t--------(2)   adding equations (1) and (2):-

40  =  2/t + 3/t
40 =  5/t
t = 5/40 = 1/8 hr 

x = 20 - 2 / 1/8  = 20 - 16 = 4

Wind speed was 4 mph Answer

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Grace rakes leaves everyday for one week. She fills the same number of bags with leaves on each of the 5 weekdays. She fills 11
svlad2 [7]

Answer:

3 bags per weekday

Step-by-step explanation:

Total bags of leaves at the end of the week = 26 bags

Bags of leaves she fills over the weekend = 11 bags

Bags of leaves she fills during weekdays = x bags

Total bags of leaves at the end of the week = Bags of leaves she fills over the weekend + Bags of leaves she fills during weekdays

26 = 11 + x

Subtract 11 from both sides

26 - 11 = 11 - 11 + x

15 = x

x = 15 bags

If she fills the same number of bags with leaves on each of the 5 weekdays.

how many bags she filled each weekday.

Bags she filled each weekday = Total Bags of leaves she fills during weekdays / 5 weekdays

= 15 bags / 5 weekdays

= 3 bags per weekday

7 0
2 years ago
Sharon was going through the financial records of her company. The profit earned by the company, p(t), over time t, in years, fo
FromTheMoon [43]
For this case what we must do is find a quadratic function that is already factored.
 This is because in the factored quadratic equations, it is easier to observe the zeros of the function.
 In this case, the zeros of the function represent the time at which the company did not make any profit.
 We have the following equation:
 p (t) = 40 (t - 3) (t + 2) (t - 5) (t + 3)
 We observed that there was no gain in:
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 Answer:
 
a.p (t) = 40 (t - 3) (t + 2) (t - 5) (t + 3)
5 0
2 years ago
A liquid vessel which is initially empty is in the form of an inverted regular hexagonal pyramid of altitude 25 feet and base ed
Misha Larkins [42]
<span>Since: v =sqrt(3)/2 s^2h 

6779 liters x 0.0353cu ft/1 liter= 239.299 cu ft 
but by proportion s/h = 10/25 
s = 10/25 h 
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h = (239.299/0.139)^(1/3) = 11.985 ft</span>
6 0
2 years ago
Read 2 more answers
Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production
Whitepunk [10]

Answer:

32% probability of a defect.

The expected number of defects for a 1000-unit production run is 320.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 10

Standard deviation = 0.15.

Probability of a defect

Weights less than 9.85 oz or greater than 10.15 oz will be classified as defects.

9.85 = 10 - 0.15

10.15 = 10 + 0.15

By the Empirical Rule, 68% of weights are between 9.85 and 10.15, that is, within the limits. 32% are not within the limits.

So there is a 32% probability of a defect.

Expected number of defects for a 1000-unit production run.

E(X) = 0.32*1000 = 320

The expected number of defects for a 1000-unit production run is 320.

5 0
2 years ago
a product online for $299 and was charged an additional $10 for shipping and handling. The customer received a rebate of $99 and
sammy [17]
The customer payed $192.4 for the product.
8 0
2 years ago
Read 2 more answers
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