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Studentka2010 [4]
2 years ago
4

Brian decided to start a dog-walking service. He's going to charge each dog owner $4.50 to walk one dog and $6.75 to walk two do

gs. Approximately how much will he earn if he walks 13 single dogs and 9 sets of two dogs?
$55.00
$75.00
$100.00
$128.00
Some help? I think its around 75.00 but I'm no good at math.
Mathematics
2 answers:
Bingel [31]2 years ago
5 0
multiply\ 13\ by\ charge\ for\ one\ dog\ and\ 9\ by\ charge\ by\ two\ dogs\\\\13*4.50\$+9*6.75\$=\\\\58.5+60.75=119.25\$\\\\
He\ will\ earn\ about\ 120\$.
nataly862011 [7]2 years ago
5 0

Answer: He will earn about $120  if he walks 13 single dogs and 9 sets of two dogs .

Step-by-step explanation:

Given : Brian's going to charge each dog owner $4.50 to walk one dog and $6.75 to walk two dogs.

If he walks 13 single dogs , then amount earned = 13 × $4.50

= $58.5                             (1)

If he walks 9 sets of two dogs, then amount earned = 9  × $6.75

=$60.75                             (2)

Add (1) and (2)

The total amount he earned =  $58.5 + $60.75              

= $119.25 ≈ $120

Hence, he will earn about $120  if he walks 13 single dogs and 9 sets of two dogs .

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For the equation ae^ct=d, solve for the variable t in terms of a,c, and d. Express your answer in terms of the natural logarithm
saveliy_v [14]

We have been given an equation ae^{ct}=d. We are asked to solve the equation for t.

First of all, we will divide both sides of equation by a.

\frac{ae^{ct}}{a}=\frac{d}{a}

e^{ct}=\frac{d}{a}

Now we will take natural log on both sides.

\text{ln}(e^{ct})=\text{ln}(\frac{d}{a})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

ct\cdot \text{ln}(e)=\text{ln}(\frac{d}{a})

We know that \text{ln}(e)=1, so we will get:

ct\cdot 1=\text{ln}(\frac{d}{a})

ct=\text{ln}(\frac{d}{a})

Now we will divide both sides by c as:

\frac{ct}{c}=\frac{\text{ln}(\frac{d}{a})}{c}

t=\frac{\text{ln}(\frac{d}{a})}{c}

Therefore, our solution would be t=\frac{\text{ln}(\frac{d}{a})}{c}.

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2 years ago
Margo deposited $100 into a savings account earning 4.5% simple annual interest. At the end of each year, she adds $100 to her a
nadezda [96]

Answer:

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year three      $300          $ 9 +$4.5 + $13.5           $ 327

Step-by-step explanation:

Simple interest for any principal is given by

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p is the amount deposited

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_______________________________________________

For year one

p = $100

r = 4.5%

t=1

I = 100*4.5*1/100 = 4.5

_______________________________________________

For year two $100 more is added to already existing $100 in account.

p = 100 +100 = $200

r = 4.5%

t=1

I = 200*4.5*1/100 = 9

_______________________________________________

For year two $100 more is added to already existing $200 in account after two years.

p = 100 +100 +100 = $300

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t=1

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_______________________________________________

There fore total  money in Margo account is

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Formulating the results in tabular form

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                                                            at the end of year

Year one       100               4.5                      104.5

year two        200           9 +4.5                     213.5

year three      300           9 +4.5 + 13.5           327

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Answer:

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Step-by-step explanation:

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x-------> the favorite positive integer

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so

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Therefore

When Jenny divides the square root of her favorite positive integer by \sqrt{2} , she gets an integer

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