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Pani-rosa [81]
2 years ago
13

he ratio table below describes the relationship between grapes and blueberries in a fruit salad. Fruit Salad Grapes (cups) Blueb

erries (cups) 2 0.5 6 1.5 20 5 24 6 Mandie is making 15 cups of fruit salad. What ratio of grapes to blueberries should she use?
Mathematics
2 answers:
scoray [572]2 years ago
3 0
The first thing you should do for this case is to graph the data you have in the statement to see the relationship between grapes and blueberries.
 The function represented by the table is
 y = 0.25x
 Then, as Mandie is making 15 glasses of fruit salad, we have:
 y + x = 15
 We have two equations and two unknowns that we must solve.
 y = 0.25x
 y + x = 15
 Resolving
 For x: 
 0.25x + x = 15
 1.25x = 15
 x = 15 / 1.25 = 12
 For y: 
 y = 0.25x = 0.25 (12) = 3
 Answer
 The ratio of grapes to blueberries she should use is 12: 3
LekaFEV [45]2 years ago
3 0

Answer: (C)

Step-by-step explanation: 12:3

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T= 300 (d−15) 2 ​ +20space, T, equals, start fraction, left parenthesis, d, minus, 15, right parenthesis, start superscript, 2,
stealth61 [152]

As can be read from your statement written "T, equals, start fraction, left parenthesis, d, minus, 15, right parenthesis, strt superscript, 2, end superscript, divided by, 300, end fraction, plus, 20", I hope your model equation is this :

T = \frac{(d-15)^{2}}{300}  + 20

Hope this is your question, if not I think you will, still be able to find an answer of your question based on this solution

As we have to find lowest average temperature, So for minimum of a function its derivative is equal to 0 there.

So lets find derivative of T function first

So first expand (d-15)^{2} as (d-15)(d-15)

we will use FOIL to multiply these

so (d-15)(d-15) = d^{2} -15d -15d +225

= d^{2} -30d +225

so we have T = \frac{d^{2} -30d +225}{300} +20

Now we will derivate each term here,300 in denominator is constant so that will come as it in in denominator.

To derivate terms in dx^{2} -30d +225 we will use power rule formula:

(x^{n} )'= nx^{n-1}

so derivative of (d^{2} )'= 2d^{2-1} = 2d^{1} = 2d

Then derivative of d will be 1

so that of -30d will be -30

then derivate of constant -225 will be 0

so we will have derivative as \frac{2d-30}{300} for the fraction part and then derivative of +20 is again 0 as its constant term

T' = \frac{2d-30}{300}

For minimum we will put this derivative =0

0 = \frac{2d-30}{300}

Now solve for d

times both sides by 300

0 \times 300 = \frac{2d-30}{300} \times 300

0 = 2d-30

0 +30 = 2d -30 +30

30 = 2d

\frac{30}{2} = \frac{2d}{2}

15 = d

So now we have to find value of lowest temperature.

For that simply plug 15 in d place in original T function equation

T = \frac{(d-15)^{2}}{300}  + 20

T = \frac{(15-15)^{2}}{300}  + 20

T = 20

So T = 20 °C is the lowest average temperature and the answer.

6 0
2 years ago
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What is 4(-8x + 5) – (-33x – 26)
chubhunter [2.5K]

Answer: x+46

Step-by-step explanation:

For this problem, you want to first distribute each term.

4(-8x+5)-(-33x-26)               [distrubute 4 and -1]

-32x+20+33x+26                  [combine like terms]

x+46

8 0
2 years ago
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Ivan found the change in a scale factor. His work is shown below. What error did Ivan make?
Tresset [83]
Scale factor is:
factor = (new length) / (old length)
Ivan correctly inserted numbers and correctly divided these two numbers by 5.

There is no error in the shown picture.
5 0
2 years ago
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X=a-2by(2) make y the subject
sladkih [1.3K]

Answer:

y = √{(a - x)/2b}

Step-by-step explanation:

x=a-2by²

2by² = a - x

divide through by 2b

y² = (a - x)/2b

y = √{(a - x)/2b}

3 0
2 years ago
What are the domain and range of f (x) = (one-fifth) Superscript x?
natka813 [3]

Answer:

The domain of the function is all real numbers (-\infty,\infty) and the range is all positive real numbers (0,\infty)

Step-by-step explanation:

We have the following function f(x)=(\frac{1}{5} )^x and we want to find the domain and the range.

The function we have is an example of an exponential function f(x)=b^x with b > 0 and b ≠ 1. This types of functions in general have the following properties:

  • It is always greater than 0, and never crosses the x-axis
  • Its domain is the set of real numbers
  • Its Range is the Positive Real Numbers (0,\infty)

The domain of a function is the specific set of values that the independent variable in a function can take on.

When determining domain it is more convenient to determine where the function would not exist.

This function has no undefined points nor domain constraints. Therefore the domain is (-\infty,\infty).

The range is the resulting values that the dependent variable can have as x varies throughout the domain. Therefore the range is (0,\infty).

We can check our results with the graph of the function.

7 0
2 years ago
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