Let S = the sophomores
Let R = the freshmen
Short Answer C
s + r = 1595 (1)
s + 15 = r (2)
Substitute for r from equation (2) into equation (1)
s + s + 15 = 1595 Combine like terms
2s + 15 = 1595 Subtract 15 from both sides
2s = 1595 - 15
2s = 1580 Divide by 2
s = 1580/2
s = 795 sophmores.
s + r = 1595
795 + r = 1595 Subtract 795 from both sides
r = 1594 - 795
r = 800 Freshmen
Answer C <<<<<<
<span>This is a perimeter of 1/4 of a circle. We know that the radius of the circle: r = 5 in. Also the perimeter of the circle is : 2 * r * Pi = 2 * 5 * 3.14 = 31.4 in. For the quarter of a circle it its 31.4 : 4 = 7.85 in. After that we can add the 2 lengths of the radius: P = 5 + 5 + 7.85 = 17.85 in ( approx. 17.9 in ). Answer: C ) 17.9 in. </span>
The diagram included should explain this.
we are given
The pump can generate a pressure of 2.3x107 pa
so,

a radius of 0.041 m
so,

a stroke lasting 29 s, the piston moves 0.57 m
so,


Firstly, we will find area



now, we can use power formula

F=pA
W=Fh
so, W=pAh
we can plug it

now, we can plug values

now, we can simplify it
Power=2386.92414 watt.........Answer
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To get the answer we need the formula or source.
The question in another way if 4cm=1.2km, what is the 10cm=--------
first, you have to use the crisscross.
4cm=1.2km
10cm= x it is variable
then, 4xx= 1.2kmx10cm
4x=12km
4x/4= 12/4
x=3km