The average marks of shahid first four papers is 88 how much mark should he get in the fifth paper so that the average of five p
2 answers:
Answer with Step-by-step explanation:
The average marks of Shahid first four papers is 88.
Let a,b,c and d be the marks in first four papers
⇒
⇒ a+b+c+d=88×4
=352
Let marks in fifth paper be x
The average of five papers become 90
⇒
⇒ a+b+c+d+x=90×5
⇒ 352+x=450 (since a+b+c+d=352)
⇒ x=450-352
⇒ x=98
Hence, Correct option is:
d.98
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Answer:
The minimum width of the placemat is 10 inches.
Step-by-step explanation:
Let suppose that placemat has a square form, whose width must be at least equal to the diameter of the pizza, so that pizza does not touch the table. Hence, the following relationship is obtained:
Where:
- Width of the placemat, measured in inches.
- Diameter of pizza, measured in inches.
The area of the pizza, measured in square inches, is determined by this formula:
The diameter is cleared afterwards:
If and
, then:
The minimum width of the placemat is 10 inches.
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Then by the additivity of definite integrals this is the same as
(presumably this is what the hint suggests to use)
Then by the fundamental theorem of calculus, we have