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11111nata11111 [884]
2 years ago
10

The average marks of shahid first four papers is 88 how much mark should he get in the fifth paper so that the average of five p

apers becom 90?
a.92
b.94
c.96
d.98
Mathematics
2 answers:
Mars2501 [29]2 years ago
7 0

Answer with Step-by-step explanation:

The average marks of Shahid first four papers is 88.

Let a,b,c and d be the marks in first four papers

⇒  \dfrac{a+b+c+d}{4}=88

⇒  a+b+c+d=88×4

                  =352

Let marks in fifth paper be x

The average of five papers become 90

⇒ \dfrac{a+b+c+d+x}{5}=90

⇒ a+b+c+d+x=90×5

⇒  352+x=450   (since a+b+c+d=352)

⇒ x=450-352

⇒ x=98

Hence, Correct option is:

d.98

Dennis_Churaev [7]2 years ago
6 0
Your answer is D. 98
88*4=352
90*5=450
hence 450-352=98

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