The average marks of shahid first four papers is 88 how much mark should he get in the fifth paper so that the average of five p
2 answers:
Answer with Step-by-step explanation:
The average marks of Shahid first four papers is 88.
Let a,b,c and d be the marks in first four papers
⇒
⇒ a+b+c+d=88×4
=352
Let marks in fifth paper be x
The average of five papers become 90
⇒
⇒ a+b+c+d+x=90×5
⇒ 352+x=450 (since a+b+c+d=352)
⇒ x=450-352
⇒ x=98
Hence, Correct option is:
d.98
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Answer: The correct option is A.
Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.
We are given the resultant polynomial which is :
One of the polynomial which are added up is :
Let the other polynomial be 'x'
According to the question:
Solving the like terms in above equation we get:
Hence, the correct option is A.
Answer:
a) F (A , B,C)(a,b,c) = abc
b) Answer is in derivative
Step-by-step explanation:
Hence area is maximum x=6
For ( a,b,c) ∈ (0,1)
We have that
F A, B,C (a,b,c) = A≤ a , B≤ b , C≤c
=P (A≤a) P (B≤b) P (C≤c)
A , B, C ≈ unit (0,1) we have that
P (A≤a) =a
P (B≤b) =b
P (C≤c)=c
Thus
F (A , B,C)(a,b,c) = abc
b) Answer is in derivative
