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2 years ago

How many points need to be removed from this graph so that it will be a function?

Mathematics

2 answers:

NemiM [27]2 years ago

8 0

3 points so it will pas the vertical line test. A function has a single y output for every x input so whatever the x, there can only be one dot at that x

aliya0001 [1]2 years ago

6 0

it would be answer choice C

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What is 62.19 x 32.5

navik [9.2K]

You have to multilpy them . answer would be 2021.175

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2 years ago

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The box plots compare the number of students in Mr. Ishimoto’s classes and in Ms. Castillo’s classes over the last two semesters

Ilya [14]

-Both box plots show the same interquartile range.
>Interquartile range (IQR) is computed by Q3-Q1.
For Mr. Ishimoto's class, Q3 is 35 and Q1 is 31. 35-31 = 4.
For Ms. Castillo's class, Q3 is 34 and Q1 is 30. 34-30 = 4.

-Mr. Ishimoto had the class with the greatest number of students.
>Mr. Ishimoto had 40 students, represented by the last data point of the whiskers.

-The smallest class size was 24 students.
>Which was Ms. Castillo's class.

7 0

2 years ago

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11) The Cost of maintaing a

dezoksy [38]

Answer:

a). Cost of 44 pupils = $14265

b). Least number of pupils = 31

Step-by-step explanation:

The given question is incomplete; here is the complete question.

The cost of maintaining a school is partly constant and partly varies as the number of pupils. With 50 pupils, the cost is $15,705.00 and with 40 pupils, it is $13,305.00.

(a) Find the cost when there are 44 pupils.

(b) If the fee per pupil is $360.00, what is the least number of pupils for which the school can run without a loss?

Let the equation representing the total cost of maintaining a school is,

C = ax + b

Where C = Total cost of maintaining a school

a = Fee per pupil

b = Fixed running cost

x = number of pupils

a). Cost of 50 pupils = $15705

Equation will be,

15705 = 50a + b -------(1)

Cost of 40 pupils = $13305

Equation will be,

13305 = 40a + b --------(2)

By subtracting equation (2) from equation (1),

15705 - 13305 = (50a + b) - (40a + b)

2400 = 10a

a = 240

From equation (1),

b = 3705

Equation representing the total cost will be,

C = 240x + 3705

If x = 44

C = 240(44) + 3705

C = $14265

b). If the fee per pupil 'a' = $360

Let the number of pupils = p

Total fee of 'p' pupils = $360p

Total cost to run the school will be = 3705 + 240p

For the school not to be in the loss,

360p ≥ 3705 + 240p

360p - 240p ≥ 3705

120p ≥ 3705

p ≥ $\frac{3705}{120}$

p ≥ 30.875

Therefore, to run the school without loss, number pupils should be at least 31.

3 0

2 years ago

The coordinate values of the vertices of △klm are integers. triangle klm has vertices located at (1, 1), (5, 4) and (5, 1). whic

worty [1.4K]

The rest of the queastion is :
 A) (-1, 1), (-1, 4), (2, 1)
B) (0, 0), (3, 4), (0, 5)
C) (-1, 1), (-4, 5), (-1, 5)
D) (0, 0), (-5, 0), (0, 4)
==============================

The distance between two points (x₁,y₁),(x₂,y₂) = d
$d = \sqrt{ (x2-x1)^{2} + (y2-y1)^{2} }$

we have K(1, 1), L(5, 4) and M(5, 1)
we will find the length between each two points.
KL = $d = \sqrt{ (5-1)^{2} + (4-1)^{2} }$ = 5
LM = $d = \sqrt{ (5-5)^{2} + (1-4)^{2} }$ = 3
KM = $d = \sqrt{ (5-1)^{2} + (1-1)^{2} }$ = 4

now check each group from the choices
the group that will give the same result will be the correct choice.
The correct choice is C
C) (-1, 1), (-4, 5), (-1, 5)

check the answer;
K'(-1, 1), L'(-4, 5), M'(-1, 5)

K'L' = $d = \sqrt{ (-4+1)^{2} + (5-1)^{2} }$ = 5
L'M' = $d = \sqrt{ (-1+4)^{2} + (5-5)^{2} }$ = 3
K'M' = $d = \sqrt{ (-1+1)^{2} + (5-1)^{2} }$ = 4

6 0

2 years ago

Beatrice graphed the relationship between the

sdas [7]

Answer:

Option C. The time in seconds that passed before the printer started printing pages

see the explanation

Step-by-step explanation:

Let

y ---->the number of pages printed.

x ---> the time (in seconds) since she sent a print job to the printer

we know that

The x-intercept is the value of x when the value of y is equal to zero

In the context of the problem

The x-intercept is the time in seconds that passed before the printer started printing pages (the number of pages printed is equal to zero)

5 0

2 years ago

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