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Elden [556K]
2 years ago
11

A retired woman has $180,000 to invest. she has chosen one relatively safe investment fund that has an annual yield of 9% and an

other, riskier fund that has a 13% annual yield. how much should she invest in each fund if she would like to earn $18,000 per year from her investments?
Business
1 answer:
Zepler [3.9K]2 years ago
6 0
Solution:  
Let the amount invested in scheme which yields 9% be x and amount invested in scheme which yields 13% be y.  
x + y = 180000 --equation 1 
0.09x + 0.13y = 18000 --equation 2  
Balancing the equations, multiply equation 1 with 0.09 and equation 2 with 1,  
0.09x + 0.09y = 16200 -equation 3
 0.09x + 0.13y = 18000 --equation4  
Subtracting equation 4 from 3, 
 -0.04y = -1800  
y = 45000 
 Now putting value of y in equation 1, 
 x + 45000 = 180000 
 x = 135000 
 The amount to be invested in scheme which yields 9% = $135,000
 The amount to be invested in scheme which yields 13% = $45,000
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Explanation:

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(Total Liabilities) = (Total Assets) - (Total Capital)    (1)

Based on equation (1), in order to compute for the total liability, we need to compute the total assets and total capital.

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Note that the total assets is obtained by adding the amount (or value) of the all the assets listed above.

Since the net income is an increase (or decrease if it's a net loss) of capital, we classify net income as capital. In particular, the net income of Shairo's at the end of first year adds to the capital at the start of first year. 

Moreover, the withdrawal of money by the owner also decreases the capital.  

Thus, the total capital at the end of first year is calculated as follows:

Capital (start of the year):            $15,000
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Note: ($2,000) means -$2,000. This notation is used in accounting.

Hence using equation (1), the total liabilities at the end of first year is given by

(Total Liabilities) = (Total Assets) - (Total Capital)
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Total Liabilities = $11,200

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Answer:

The Linear programming model is given as below

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Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

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2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

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3X+4Y+6Z\leq 240

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As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

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\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

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\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

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2X+2Y+Z\leq 400

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\dfrac{4X+6Y+5Z}{40}\leq 8

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