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Novay_Z [31]
2 years ago
12

Which piece of additional information can be used to prove that △RST ~ △VUT?

Mathematics
2 answers:
saw5 [17]2 years ago
5 0

  ∠R ≅ ∠V......................

inna [77]2 years ago
3 0

Answer:- ∠R≅ ∠ V is the piece of additional information can be used to prove that △RST ~ △VUT.


Explanation:-

Given:- Two triangles △RST and △VUT joined by vertex T such that RV and US are two line segments.

The additional information is ∠ R≅ ∠ V which can be used to prove that △RST ~ △VUT.

Let we assume that it is given ∠R≅ ∠ V then

Proof :- In △RST and △VUT

∠RTS≅∠VTU   [∵vertically opposite angles are congruent]

∠R≅∠V   [given]

⇒△RST ~ △VUT by AA similarity criteria.

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An arrow is shot at an angle of θ=45∘ above the horizontal. The arrow hits a tree a horizontal distance D=220m away, at the same
Alborosie

Let us solve the Part A first. 

In order to find the time we use the formula for the range of a projectile:

R = v^2 multiply by sin(2θ) divided by g

220 = v^2 multiply by sin(2 multiply by 45) divided by 9.8

220 = v^2 divided by 9.8

V^2 = 2,156

v = 46.43 m/s

Now we will find the x component of the velocity:

vx = sin(θ) multiply by v

vx = cos(45) multiply by 46.43

vx = 32.83 m/s

So the time it takes for the arrow to travel 220 m is the same as the time it is in the air:

time = d divided by  v

time = 220 divided by 32.83

time = 6.70 seconds

6.70 s.

Now we will solve the part B.

We will start by finding the time it takes for the apple to fall 6.0 m

d = v0 multiply by t + 1 divided by 2 at 2 square

6 = 0 multiply by t + 1 <span>divided by </span>2 multiply by 9.8 multiply by t^2

6 = 4.9 multiply by t^2

<span>t^2 = 1.2245</span>

t = 1.1066 s

Thus the arrow needs 6.70 s to reach the tree, so we will just subtract for the difference:

wait = 6.70 – 1.1066

wait = 5.59 s

Hence the apple should be dropped 5.59 s after the arrow is shot.

I hope it helped

5 0
2 years ago
Read 2 more answers
Create a set of data that contains 11 test scores and satisfies each condition below:Mean: 83Median: 81Mode: 80Range: 26
Lunna [17]

64 78 80 80 80 81 81 82 83 89 90 Not ecaxt but close, it should help atleast, everything is right except mean

4 0
2 years ago
IM OFFERING 100 POINTS, I NEED HELP AND ITS TIMED
Assoli18 [71]

Answer:

look below

Step-by-step explanation:

Part A: The y-intercept is $1,500

The x-intercept is 20 days

Part B: Equation of the line in point-slope form is  y - 1350 = -75×(x - 2) Equation of the line in slope-intercept form is y = -75·x + 1500

Equation of the line in standard form  is y + 75·x = 1500  

Part C:

f(x) = -75·x + 1500

Part D: $1,125 Step-by-step explanation: The information given are; x,                 g(x) 0,                 $1,500 2,                 $1,350 4,                 $1,200 The equation of a straight line relation between the x, and y, coordinates in slope and intercept form is  y = m·x + c Where; m = The slope c = The y-intercept From the data, we have two points, (x₁, y₁), (x₂, y₂) given as (0, 1,500), (2, 1350); The y-intercept = y at x = 0 = 1,500 y = -75·x + 1500 x = 1500/75 = 20  

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/5966450-the-table-of-values-represents-a-linear-function-g-x-where-x-is.html

I hope this helps I know its kinda confusing

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Advocard [28]


3/2x +7/4x = ...........

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4 0
2 years ago
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Ostrovityanka [42]

Answer:

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3 0
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