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tatuchka [14]
2 years ago
12

A combination washer/dryer costs $1,179. New parts for this washer/dryer cost $211, labor to repair it costs $553, and shipping

it to and from a repair center costs $152. A full warranty, which covers all aspects of repairing the washer/dryer, costs 30% of the price of the washer/dryer. A limited warranty, which only covers labor costs, only costs 14% of the price of the washer/dryer. Assuming that the washer/dryer needs repairs which include parts, labor, and shipping, which warranty is the better deal, and by how much, rounded to the nearest dollar? a. The limited warranty will end up costing the consumer $189 less. b. The limited warranty will end up costing the consumer $363 less. c. The full warranty will end up costing the consumer $553 less. d. The full warranty will end up costing the consumer $174 less.
Mathematics
2 answers:
Vera_Pavlovna [14]2 years ago
4 0

Answer:

its d

Step-by-step explanation:

Keith_Richards [23]2 years ago
3 0
The better deal is the Full Warranty, by approximately 174 dollars. To solve the cost of the full warranty, simply multiply 30 percent times the cost of the washer/dryer.30 x 1,179 = 353.70. You do not need to add anything to this because the warranty covers the extra costs. To solve for the cost of the limited warranty, multiply 14 percent times the cost of the washer/dryer, plus the cost of the new parts and the repair center costs (the warranty only covers the labor repair costs): (.14 x 1,179) + 211 + 152 --> 165.06 + 211 + 152 = 528.06. The full warranty is clearly cheaper. To figure out by how much, simply subtract the full warranty from the limited warranty: 528.06 - 353.70 = 174.36. To round to the nearest number, take off the decimal: 174. So that means your answer is D hope this helps.
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What additional information could you use to show that ΔSTU ≅ ΔVTU using SAS? Check all that apply.
GalinKa [24]

Options

A. UV = 14 ft and m∠TUV = 45°

B. TU = 26 ft

C. m∠STU = 37° and m∠VTU = 37°

D. ST = 20 ft, UV = 14 ft, and m∠UST = 98°

E. m∠UST = 98° and m ∠TUV = 45°

Answer:

A. UV = 14 ft and m∠TUV = 45°

D. ST = 20 ft, UV = 14 ft, and m∠UST = 98°

Step-by-step explanation:

Given

See attachment for triangle

Required

What proves that: ΔSTU ≅ ΔVTU using SAS

To prove their similarity, we must check the corresponding sides and angles of both triangles

First:

\angle UST must equal \angle UVT

So:

\angle UST = \angle UVT = 98

Next:

UV must equal US.

So:

UV = US = 14

Also:

ST must equal VT

So:

ST = VT = 20

Lastly

\angle TUV must equal \angle TUS

So:

\angle TUV = \angle TUS = 45

Hence: Options A and D are correct

4 0
1 year ago
A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr
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Answer:

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034

The estimated standard error is:

\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096

The confidence interval for the difference in proportions is

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<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

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