Answer:
z= 0.278
Step-by-step explanation:
Given data
n1= 60 ; n2 = 100
mean 1= x1`= 10.4; mean 2= x2`= 9.7
standard deviation 1= s1= 2.7 pounds ; standard deviation 2= s2 = 1.9 lb
We formulate our null and alternate hypothesis as
H0 = x`1- x`2 = 0 and H1 = x`1- x`2 ≠ 0 ( two sided)
We set level of significance α= 0.05
the test statistic to be used under H0 is
z = x1`- x2`/ √ s₁²/n₁ + s₂²/n₂
the critical region is z > ± 1.96
Computations
z= 10.4- 9.7/ √(2.7)²/60+( 1.9)²/ 100
z= 10.4- 9.7/ √ 7.29/60 + 3.61/100
z= 0.7/√ 0.1215+ 0.0361
z=0.7 /√0.1576
z= 0.7 (0.396988)
z= 0.2778= 0.278
Since the calculated value of z does not fall in the critical region so we accept the null hypothesis H0 = x`1- x`2 = 0 at 5 % significance level. In other words we conclude that the difference between mean scores is insignificant or merely due to chance.
Answer:
10 to power of -8 so 0.00000001 I think
Answer:
C. x² − 8x + 24 − 72/(x+3)
Step-by-step explanation:
See attached picture for long division method.
Logically, we know x³ − 5x² factors to x² (x − 5). Since x + 3 isn't a factor, we know the remainder isn't 0. So we can narrow the options down to A or C.
One way to find the remainder is through long division. Or, since this is multiple choice, we multiply the options by x + 3 and see which one results in an answer of x³ − 5x².
(x + 3) (x² − 8x + 24 − 72/(x+3))
(x + 3) (x² − 8x + 24) − 72
x³ − 8x² + 24x + 3x² − 24x + 72 − 72
x³ − 5x²
Answer:
The largest possible area of the deck is 87.11 m² with dimensions;
Width = 9.33 m
Breadth = 9.33 m
Step-by-step explanation:
The area of a given dimension increases as the dimension covers more equidistant dimension from the center, which gives the quadrilateral with largest dimension being that of a square
Given that the railings will be placed on three sides only and the third side will cornered or left open, such that the given length of railing can be shared into three rather than four to increase the area
The length of the given railing = 28 m
The sides of the formed square area by sharing the railing into three while the fourth side is left open are then equal to 28/3 each
The area of a square of side s = s²
The largest possible area of the deck = (28/3)² = 784/9 = 87.11 m² with dimensions;
Width = 28/3 m = 9.33 m
Breadth = 28/3 m = 9.33 m.
Hello! For this question, first, we have to find the area of the spherical container. The formula for finding the area of a sphere is 4/3πr³. We raise the radius to the 3rd power and multiply it by pi (3.14). The radius is 9 cm. 9³ is 729. There's that number. Now, we multiply 81 by 3.14 to get the total area of the square. 729 * 3.14 is 2,289.06. Now, multiply that by 4/3. 2,289.06/1 * 4/3 is 3,052.08. The volume of the sphere is 3,052.08 cubic centimeters. Which brings us to the next part. Now, we can find the price of the solution by multiplying the area by the price. 3,052.08 * 2.10 is 6,409.368 or 6,409.37 when rounded to the nearest cent. The total value of the solution in the container is $6,409.37.
