Answer: x^2+2x-8<0
Step-by-step explanation:
A. x^2 - 2x - 8 < 0
(x - 4)(x + 2) < 0
B. x^2 + 2x - 8 < 0
(x + 4)(x - 2) < 0
C. x^2 - 2x - 8 > 0
(x - 4)(x - 2) > 0
D. x^2 + 2x - 8 > 0
(x + 4)(x - 2) > 0
When you test a point in the interval between -4 and 2, for example 0, it is negative.
Answer:
14p -3
Step-by-step explanation:
-7p 3(4p 2+3p - 1)
3x4= 12p
3x3=9p
12+9= 21
21-7=14p
3x2=6
3x-3=-9
-9 +6= -3
= 14p -3
hope this helps :)
Answer:
Ratio of the perimeters =3:1
Step-by-step explanation:
We have given that : Ratio of the sides of two squares is 3:1
To find : Ratio of their perimeters
Solution : Let the length of the sides are 3:1 = 3x : x
Formula of perimeter of square = 4(side)
Using the formula ,
Perimeter of 1 square = 4×3x= 12x
Perimeter of 2 square = 4×x= 4x
Ratio of the perimeter of 1 square and 2 square = 12x : 4x
= 3 : 1
AnswBrainly User
When x = 6.4, y=117, therefore
15*6.4 + b = 117
b = 117 - 96 = 21
Confirm this value by checking (6.6, 120).
15*6.6 + 21 = 120 (Correct)
Answer: b = 21
Step-by-step explanation:
Let p(x) be a polynomial, and suppose that a is any real
number. Prove that
lim x→a p(x) = p(a) .
Solution. Notice that
2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .
So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial
long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x –
2.
Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number
such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| <
1, so −2 < x < 0. In particular |x| < 2. So
|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|
= 2|x|^3 + 5|x|^2 + |x| + 2
< 2(2)^3 + 5(2)^2 + (2) + 2
= 40
Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2
+ x − 2| < ε/40 · 40 = ε.
