Salt flows in at a rate of (5 g/L)*(3 L/min) = 15 g/min.
Salt flows out at a rate of (x/10 g/L)*(3 L/min) = 3x/10 g/min.
So the net flow rate of salt, given by
in grams, is governed by the differential equation,

which is linear. Move the
term to the right side, then multiply both sides by
:


Integrate both sides, then solve for
:


Since the tank starts with 5 g of salt at time
, we have


The time it takes for the tank to hold 20 g of salt is
such that

X²+5x+5 has zeroes given by x=(-5±√25-20)/2=(-5±√5)/2=-1.3820 and -3.6180.
In simplest radical form the zeroes are -5/2+√5/2 and -5/2-√5/2.
Answer:
- Fresh Pond: p(t) = 854 +3t
- Strawberry: p(t) = 427·1.10^t
Step-by-step explanation:
(a) The general term of an arithmetic sequence is ...
an = a1 + d(n -1)
If we let the sequence of population numbers be modeled by this, and we use t for the number of years, we want n=1 for t=0, so n = t+1 and we have ...
p(t) = 854 +3(t+1-1)
p(t) = 854 +3t
__
(b) The general term of a geometric sequence is ...
an = a1·r^(n-1)
were r is the common ratio. Here, the multiplier from one year to the next is 1+10% = 1.10. Again, n=t+1, so the population equation is ...
p(t) = 427·1.10^(t+1-1)
p(t) = 427·1.10^t
Answer:
<h3>The answer is 6 units</h3>
Step-by-step explanation:
The distance between two points can be found by using the formula

where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
K (5, 6) P (1, 1)
The distance from K to P is

We have the final answer as
<h3>6 units to the nearest whole number</h3>
Hope this helps you